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MArishka [77]
3 years ago
15

the common ratio of a geometric series is 3 and the sum of the first 8 terms is 3280. what is the first term of the series?

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer: 1

Step-by-step explanation:

The formula for calculating the sum of a Geometric series if the common ratio is greater than 1 is given as :

S_{n} = \frac{a(r^{n}-1) }{r-1}

Where S_{n} is the sum of terms , a is the first term , r is the common ratio and n is the number of terms.

From the question:

S_{n} = 3280

a = ?

r = 3

n = 8

Substituting this into the formula , we have

3280 = \frac{a(3^{8}-1) }{3-1}

3280 = \frac{a(6561-1)}{2}

Multiply through by 2 , we have

6560 = a ( 6560)

divide through by 6560, we have

6560/6560 = a(6560)/6560

Therefore : a = 1

The first term of the series is thus 1

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True

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Answer: 1590cm^3

Step-by-step explanation:

V=\frac{3\sqrt{3} }{2}a^2h

a = base

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V=\frac{3\sqrt{3} }{2}(6cm)^2(17cm)

Solve the parentheses squared first.

V=\frac{3\sqrt{3} }{2}(36cm^2)(17cm)

2 and 36 can be simplied

2/2=1

36/2=18

V=3\sqrt{3}(18cm^2)(17cm)

V=3\sqrt{3}(306cm^3)\\ V=1590.02cm^3

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3 0
3 years ago
1(x-2)= -5.5 solve for x
STatiana [176]

Answer:

-3.5

Step-by-step explanation:

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The amount of money in a savings account after t years is represented by the function f(t)=500(1.015)^t. What does the value 500
MaRussiya [10]

Answer:

Find out the what does the value 500 represent in this situation .

To prove

As given

The amount of money in a savings account after t years is represented by the function.

f(t)=500(1.015)^{t}

Exponential function for amount is given by .

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Wher a is the initial value, r is the rate in decimal form and t is the time.

Compare the functions

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and

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Therefor $500 is the initial value .


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