Let the numbers be x and y, then
2x + y = 47 . . . (1)
x + 3y = 56 . . . (2)
(2) x 2 => 2x + 6y = 112 . . . (3)
(1) - (3) => -5y = -65 => y = -65/-5 = 13
From (2), x + 3(13) = 56 => x = 56 - 39 = 17
The two numbers are 13 and 17.
Answer:
0.3721 or 37.21%
Step-by-step explanation:
P(I) = 0.60; P(II) = 0.40;
P(not defective I) = 0.90; P(not defective II) = 0.80
The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

The probability is 0.3721 or 37.21%.
Answer:
B will be the answer...
Step-by-step explanation:
The second equation in system B is only in terms of y, so we need to use elimination to eliminate the x term from the second equation in system A.
To do that, we need to multiply the first equation by 5.
5 (-x − 2y = 7)
-5x − 10y = 35
Add to the second equation. Notice the x terms cancel out.
(-5x − 10y) + (5x − 6y) = 35 + (-3)
-16y = 32
Combining this new equation with the first equation from system A will get us system B.
-x − 2y = 7
-16y = 32
Answer:
$22.50....................
Function number one , the graphing seems good