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Mkey [24]
3 years ago
14

Mr. Kuo’s checking account had a balance of $512.45

Mathematics
2 answers:
Ugo [173]3 years ago
5 0

Answer:

63753.8888

Step-by-step explanation:

Blababa [14]3 years ago
3 0

Answer:

1104.64 :) he rich rich

You might be interested in
Simplify the expression 3x²-5x-4+xy-(2xy+2x²) then evaluate the result if x=-1 and y=6
lidiya [134]
3x²-5x-4+xy-(2xy+2x²) Simplified is x²-5x-4-xy
5 0
3 years ago
Read 2 more answers
The blades of a windmill turn on an axis that is 35 feet above the ground. The blades are 10 feet long and complete two rotation
Alona [7]

Answer:

h = 10sin(π15t)+35

Step-by-step explanation:

The height of the blade as a function f time can be written in the following way:

h = Asin(xt) + B, where:

B represets the initial height of the blade above the ground.

A represents the amplitud of length of the blade.

x represents the period.

The initial height is 35 ft, therefore, B = 35ft.

The amplotud of lenth of the blade is 10ft, therefore A = 10.

The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π

Finally the equation that can be used to model h is:

h = 10sin(π15t)+35

5 0
3 years ago
Read 2 more answers
ACCTUALLY HELP ME??!!!!!!! NEEDED FOR TOMORROW AND 50 POINTS! will award brainliest for first answer!!
drek231 [11]

Answer:

a:c = 35:24

a:c = 20:27

a:c = 35:22

a:c = 28:27

Step-by-step explanation:

a:b = 7:3

Using cross products

3a = 7b

Divide by 7

3a/7 = b

Now we want

8b = 5c

Substitute in 3a/7 for b

8 (3a/7) = 5c

24/7a = 5c

Multiply by 7

24/7a *7 = 5*7c

24a = 35c

Divide by c

24 a/c = 35

Divide by 24

a/c = 35/24

a:c = 35:24

a:b = 4:9

Using cross products

9a = 4b

Divide by 4

9a/4 = b

Now we want

3b = 5c

Substitute in 9a/4 for b

3 (9a/4) = 5c

27/4a = 5c

Multiply by 4

27/4a *4 = 5*4c

27a = 20c

Divide by c

27 a/c = 20

Divide by 27

a/c = 20/27

a:c = 20:27

b:c = 5:11

Using cross products

11b = 5c

Divide by 11

b = 5c/11

Now we want

2a = 7b

Substitute in 5c/11 for b

2a = 7(5c/11)

2a = 35c/11

Multiply by 11

2a*11 = 35c

22a = 35c

Divide by c

22 a/c = 35

Divide by 22

a/c = 35/22

a:c = 35:22

b:c = 14:3

Using cross products

3b = 14c

Divide by 3

b = 14c/3

Now we want

9a = 2b

Substitute in 14c/3 for b

9a = 2(14c/3)

9a = 28c/3

Multiply by 3

9a*3 = 28c

27a = 28c

Divide by c

27 a/c = 28

Divide by 27

a/c = 28/27

a:c = 28:27

7 0
3 years ago
Let f(x)=x^2-5x+8 and g(x)=x^2-4 (f-g)(x)=
Bogdan [553]
What you do here is subtract g from f: x^2 - 5x + 8 - (x^2 -4); x^2 - 5x + 8 - x^2 + 4; Rearranging gives you x^2 - x^2 - 5x + 8 + 4 which is, simplified, -5x + 12
8 0
3 years ago
How to solve all of this
photoshop1234 [79]
Start circle: πd = (3.14)(19) = 59.7

Move diagonally to the circle with the radius of 6.2.

Second circle: 2πr = 2(3.14)(6.2) = 39

Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

Fourth circle: πd = (3.14)(16.6) = 52.2

Move down to the circle with the diameter of 7.7

fifth circle: πd = (3.14)(7.7) = 24.2

Move down to the circle with the diameter of 50

Sixth circle: πd = (3.14)(50) = 157.1

Move left to the circle with the radius of 11.8

Seventh circle: 2πr = 2(3.14)(11.8) = 74.1

Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

ninth circle: πd = (3.14)(1.1) = 3.5

Move right to the circle with the radius of 14.8

10th circle = 2πr = 2(3.14)(14.8) = 93

Move up to the end.

Hope this helps :) 
7 0
3 years ago
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