Answer:
1 / x^8
Step-by-step explanation:
We know that a^b / a^c = a^ (b-c)
x^7 / x^ 15 = x^ (7-15) = x^-8
We also that that a^-b = 1/ a^b
x^-8 = 1 / x^8
Distribute:
= 4x ( x^3) + (4x)(-6) + (-7) (x^3) + (-7) (-6)
= 4x^4 + -24x + -7x^3 + 42
= 4x^4 - 7x^3 - 24x + 42
Good luck :)
If you evaluate your polynomial at x= - 3, the polynomial = 0. So, that means ( x + 3 ) is a factor. Either using long division, or synthetic division, you'll find out that 2x^3 - 9x^2 + 3x + 4 remains. Then if you try x = 4 on that remaining polynomial, it will = 0. Use long division or synthetic division to find out that 2x^2 - x - 1 is left over. That trinomial factors into ( 2x + 1 ) ( x - 1 ).
factored form is ( x+3 )( x - 4 )( 2x + 1 )( x - 1 )
