3 years ago

Let f and g be functions given by f(x)=x^3 and g(x)=x^2 lxl

Mathematics

1 answer:

adell [148]3 years ago

4 0

I post an image instead.
Correction: g(3)=(3²)|3|=9(3)=27

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David has a bag of coins. The bag contains 7 dimes, 2 nickels, and 6 pennies. He will randomly select 2 coins from the bag one a

julia-pushkina [17]

7 out of 17 coin in the bag

7 0

3 years ago

Please help me have to turn it in 30 minutes.

Anestetic [448]

24+15+11=50, the total number of times the markers were chosen.

Since 11 of these 50 tries resulted in a red and blue marker, the probability is 11/50. This is equal to 0.22 or 22%.

4 0

2 years ago

A planter box can hold 3, ft of soil. The area of the base of the box is 24 ft. A sketch of the box is shown.

liraira [26]

Answer:

24 divided by 3= 8

8x3=24 ft

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2 years ago

How do u do this please

blagie [28]

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Hope this helps

Step-by-step explanation:

4 0

2 years ago

One variable examined is the survival rate 10 years after tagging. The scientists observed that 10 of the 50 metal tagged pengui

Oksana_A [137]

Answer: 90% confidence interval would be $(-0.2483,-0.0717)$

Step-by-step explanation:

Since we have given that

n₁ = 50

Number of metal tagged penguins survived = 10

So, $p_m=\dfrac{10}{50}=0.2$

n₂ = 50

Number of electronic tagged penguins = 18

So, $p_e=\dfrac{18}{50}=0.36$

So, at 90% confidence interval, z = 1.28

So, interval would be

$(p_m-p_e)\pm z\sqrt{\dfrac{p_m(1-p_m)}{n}+\dfrac{p_e(1-p_e)}{n}}\\\\=(0.2-0.36)\pm 1.28\sqrt{\dfrac{0.2\times 0.8}{50}+\dfrac{0.36\times 0.64}{50}}\\\\=-0.16\pm 0.0883\\\\=(-0.16-0.0883,-0.16+0.0883)\\\\=(-0.2483,-0.0717)$

Hence, 90% confidence interval would be

$(-0.2483,-0.0717)$

6 0

2 years ago