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stiks02 [169]
3 years ago
6

Solve the equation 2a+b=2a, where a and b are nonzero, real numbers. Describe the solution to this equation and justify your des

cription.
Mathematics
1 answer:
ss7ja [257]3 years ago
3 0
<span>To solve this equation we can first assume that both a and b are nonzero real numbers. Hence, A = 1 b = 1 <span><span>
1.   </span>2 (1) + 1 = 2(1)</span> <span><span>
2.   </span><span> 2 + 1 = 2: now this a false equation since there is not equality, the equation cannot retain the equal sign but will become 2 + 1 > 2. Leaving the relationship unequal.

</span></span>However, the alternative to this problem is to be b = 0. To oversee the rule in order to solve the equation retaining it as an “equation”. Further, there is no other solution for this equation. A = 1 b = 0
<span>1.   Which becomes 2(1) + 0 = 2(1)</span> <span><span>
2.   </span><span> 2 + 0 = 2 :
3.    2 = 2. Here we can observe the equality. </span></span> </span>
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PLEASE HELP!
butalik [34]
We know for the problem that the performer earned $120 at a performance where 8 people attend. We also know that he u<span>ses 43% of the money earned to pay the costs involved in putting on each performance, so we need to find the 43% of $120. To do that, we are going to divide 43% by 100%, and then multiply it by $120:
</span>\frac{43}{100}*120=51.6
Now we know that the performer uses $51.6 of $120 to pay the costs involved in putting on each performance. The only thing left to find his profits is subtract $51.6 from $120:
120-51.6=68.4

We can conclude that the performer makes a profit of $68.4 when 8 people attend his performance.
 
3 0
3 years ago
Help me with this pls
swat32

Answer:

180

Step-by-step explanation:

guessed the answer

that was the easiest

4 0
3 years ago
The graph below shows the value of Edna's profits f(t), in dollars, after t months:
umka21 [38]
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), x=6 and x=18 are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
x=6
x-6=0
x=18
x-18=0

(x-6)(x-18)=x^{2}-6x-18x+108
=x^{2}-24x+108

Now that we have our quadratic function, we are going to use the average formula: m= \frac{f(9)-f(3)}{9-3}
where
f(9) is the function evaluated at  the <span>9th month
</span>f(3) is the function evaluated at the 3rd month 

m= \frac{f(9)-f(3)}{9-3}
m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}
m= \frac{-27-45}{6}
m= \frac{-72}{6}
m=-12

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>

6 0
3 years ago
Read 2 more answers
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