Diagonals AC and BD form right angles at point M

Figure AAA is a scale image of figure BBB.

Vadim26 [7]

Figure A maps to figure B with a scale factor of 4/9, hence the value of x is x = 54

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial point to a new location. Types of transformation are<em> reflection, rotation, translation and dilation.</em>

Dilation is the increase or decrease in the size of a figure.

Figure A maps to figure B with a scale factor of 4/9, hence:

4/9 * x = 16

x = 54

Figure A maps to figure B with a scale factor of 4/9, hence the value of x is x = 54

Find out more on transformation at: brainly.com/question/4289712

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8 0

2 years ago

At a jeans factory, a random quality check found 8 pairs defective and 292 pairs with no problems. how many defective pairs can

anygoal [31]

Hello!

to solve this equation, you have to find the percentage of defects out of the total amount of jeans. if there are 300 pairs of jeans with 8 faulty pairs, then the percentage of defects would be 2.666(etc). 2.666(etc) percent of 3000 is roughly 80 pairs of defective jeans.

therefore your final answer would be 80 pairs of jeans!

6 0

2 years ago

Maurice's teacher asked him to compare the mean and median of the data distribution explain and correct Maurice's error in compa

Dmitry_Shevchenko [17]

The first part where he mentions "The distribution is skewed right" is correct. The tail on the right hand side is pulled longer than it should be, or longer compared to the left tail. "Right skew" or "skewed right" is the same as "positively skewed". They all mean the same thing.

The portion where Maurice says "This implies that the mean is less than the median" is incorrect. This is where his error is located. The reason for the error is because it should be "The mean is greater than the median" when we have right-skewed data like this.

Here's one example to see why this is the case. Consider the distribution {1,2,3,4,5}. We can see that the median is 3 since it's directly in the center. The mean is also 3 since we add up all the values and divide by 5. Symmetric data has mean = median. Now, we'll replace the '5' with something much larger to get a large outlier. Let's say we have the set {1,2,3,4,55}. The median is still 3. The outlier doesn't pull on the median. However, the mean has changed and it is (1+2+3+4+55)/5 = 65/5 = 13. The mean went from 3 to 13. Therefore, mean > median here. The mean is affected by outliers. Think of it like the outlier is pulling on the mean in a sort of magnetic way. This outlier makes the mean larger than it should be. If the outlier is extreme enough, then it sometimes makes sense to consider the trimmed mean as opposed to the regular arithmetic mean. The trimmed mean is the mean of the main cluster of values ignoring the outlier(s).

-----------------------

To recap:

If we have right skewed data, then mean > median

As you can probably guess, if we had left-skewed data, then mean < median. In symmetric data, mean = median.

4 0

2 years ago

The length of a rectangle is four times its width. if the area of the rectangle is 400 yd2 , find its perimeter.

Rus_ich [418]

I don’t know for sure but the length is 40 and the width is 10.

5 0

3 years ago

Read 2 more answers

a two digit number has the following properties. If you add the digits together and multiply the result by 10, you will get 9 mo

konstantin123 [22]

Answer:

10, 11, 12, 13, 14, 15, 16, 17, 18, 19

Step-by-step explanation:

A two-digit number can be written as:

a*10 + b

Where a and b are single-digit numbers.

a is the tens digit

b is the units digit.

the reverse number is:

b*10 + a

We know that:

"If you add the digits together and multiply the result by 10, you will get 9 more than the reverse number"

Then:

(a + b)*10 = b*10 + a + 9

We now need to solve this for a and b, where the other restriction that we have is that a and b can be any whole number of the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

Then:

(a + b)*10 = b*10 + a + 9

a*10 + b*10 = b*10 + a + 9

subtracting b*10 in both sides, we get:

a*10 = a + 9

solving this for a, we get:

a*10 - a = 9

a*(10 - 1) = 9

a*9 = 9

a = 9/9

a = 1

and notice that we do not have any restriction for b. So b can be any number of the set.

for example, if b = 2

a*10 + b = 12

now let's test the property:

10*(1 + 2) = 2*10 + 1 + 9

30 = 20 + 10 = 30

now if b = 4, we have:

a*10 + b = 1*10 + 4 = 14

10*(1 + 4) = 4*10 + 1 + 9

50 = 50

So we can see that for any value of b, this will work.

So the only restriction that we have, is that a must be equal to 1.

Then the numbers are:

10, 11, 12, 13, 14, 15, 16, 17, 18, 19

4 0

3 years ago