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jeyben [28]
3 years ago
11

PLEASE HELP ME WITH THIS

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
Let's start with the drawing. (See the drawing at the bottom of this answer.)

Draw a vertical segment.
At the bottom endpoint, draw a horizontal segment to the right.
The angle at the bottom left is a right angle.
So far this should look like an "L" shape.
The vertical segment is the wall, and the horizontal segment is the ground.

Now draw a segment that connects the right endpoint of the horizontal segment and the top endpoint of the vertical segment. Now you have a right triangle. The diagonal segment represents the ladder. The diagonal segment is the hypotenuse. Label the diagonal segment, the hypotenuse, 12 ft.
Label the vertical segment, the wall, 11.8 ft.

The angle at the bottom right is A. It is the angle the ladder makes with the ground. This angle cannot be greater than 75 degrees.

Now we use trigonometry to find the measure of angle A.

For this right triangle, and its angle A, you have a hypotenuse that measures 12 ft, and an opposite leg that measures 11.8 ft.
We need to find angle A.
The trig ratio that relates the opposite leg and the hypotenuse is the sine.

\sin A = \dfrac{opp}{hyp}

\sin A = \dfrac{11.8}{12}

\sin A = 0.98333

Since the sine of angle A equals 0.98333, we use the inverse sine function to find the measure of angle A.

A = \sin^{-1} 0.98333

A = 79.5^\circ

Answer:
The angle the ladder makes with the ground is 79.5 degrees which is greater than 75 degrees, so the ladder it will be unsafe in this position.


           |\
           |  \
           |    \
           |      \
opp = |         \ hyp = 12
= 11.8  |           \
           |             \
           |_______\  A
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What is the slope of the line that passes through the points (-2, 3)(−2,3) and (-14, -5) ?(−14,−5)? Write your answer in simples
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7 0
2 years ago
HELP!!! Anyone know how to solve I know the answer is (-3) but I don’t know how to get there. Thanks!!
Dima020 [189]

Answer:   v = -3

=========================================

Work Shown:

5 = \sqrt{-2-6v}+1\\\\5-1 = \sqrt{-2-6v}\\\\4 = \sqrt{-2-6v}\\\\4^2 = \left(\sqrt{-2-6v}\right)^2 \ \text{ .... square both sides}\\\\16 = -2-6v\\\\16+2 = -6v\\\\18 = -6v\\\\-6v = 18\\\\v = 18 \div (-6)\\\\v = -3

As you can see, we don't square both sides until the square root portion is fully isolated or on its own side. So it happens after we subtract 1 from both sides.

Technically, you are able to square both sides without first isolating the square root. But that would mean you'd have to use the FOIL rule and things would get a bit messier than they have to be. Not to mention that the square root term wouldn't fully go away (so you'd have to square again later down the line).

------------------

Checking the answer:

Replace every copy of v with -3. Simplify both sides. We should end up with the same number on each side

5 = \sqrt{-2-6v}+1\\\\5 = \sqrt{-2-6(-3)}+1\\\\5 = \sqrt{-2+18}+1\\\\5 = \sqrt{16}+1\\\\5 = 4+1\\\\5 = 5\\\\

The answer is confirmed.

4 0
3 years ago
Can you help me with this, please?​
Tema [17]

Answer:

its D i do belive

Step-by-step explanation:

4 0
3 years ago
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