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Alchen [17]
3 years ago
13

Counterexample for: The sum of a negative and a positive number is always negative

Mathematics
1 answer:
vredina [299]3 years ago
4 0

Answer:

The sum of a negative and a negative is always a positive

Step-by-step explanation:

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Step-by-step explanation:

5x+8(5+2)

5x+8(7)

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the answer is $4750.

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Divide by long division method 4x³-x+1by(2x-1)
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\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x​2​​]=​⎣​⎢​⎢​⎢​⎢​⎡​​​2​​3​​2​​​​​3​​√​(432by+√​(−6912+41472by+103680by​2​​+55296by​3​​)​​​)​​​​​−1+i√​3​​​+2by+(−2i)√​3​​​by​​+​​3​​√​2​​​​​​24​​−​3​​√​(432by+√​(−6912+41472by+103680by​2​​+55296by​3​​)​​​)​​​​​+(​24​​−1​​i)√​3​​​​3​​√​(432by+√​(−6912+41472by+103680by​2​​+55296by​3​​)​​​)​​​​​​⎦​⎥​⎥​⎥​⎥​⎤​​
totally answer.
4 0
3 years ago
FREE BRAINLIEST!!!!!!
vivado [14]

Let's solve the first inequality at first. So,

−2(x + 4) + 10 < x − 7

-2x- 8 + 10 < x - 7 By distribution property.

-2x + 2 < x - 7 Adding the like terms.

-2x < x - 7 - 2 Subtract 2 from each sides.

-2x < x - 9 By simplifying.

-2x - x < -9 Subtract x from each sides.

-3x < -9

-\frac{3x}{3}

Since we are dividing by negative 3. So, sign of inequality will get change.

So, x>3

Now the next inequality is,

−2x + 9 > 3(x + 8)

-2x + 9 > 3x + 24

-2x > 3x + 24 - 9

-2x > 3x + 15

-2x - 3x > 15

-5x >15

-\frac{5x}{-5} >\frac{15}{-5}

So, x <-3

Hence, the correct choice is x > 3 or x < −3.

7 0
3 years ago
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