Number 4 is correct a^0=1 for all real number a
number 5
y^2(y^2=y^(2+2)=y^4 correct
y^6/y^2=y^(6-2)=y^4 correct
y^0=1 false
y^9/y^5=y^(9-5)=y^4 correct
y^4(y^1)=y^(4+1)=y^5 false
The solution of the equation is given by (-2,-1), This is represented by option C.
<h3>What is a System of Equations?</h3>
A system of equations is a set of equation that have a common solution.
The solution of the equations can be determined by using the Elimination and Substitution method
3x-5y = -1
2x-y = -3
-7x = 14
x = -2
Substituting this value in the equation
3 * (-2) -5y = -1
-6 -5y = -1
-5y = 5
y = -1
Therefore, the solution of the equation is given by (-2,-1), This is represented by option C.
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Answer:
k = -2.
Step-by-step explanation:
5(3 - 2k) = 2k + 39 Distribute the 5 over the parentheses:
15 - 10k = 2k + 39
15 - 39 = 2k + 10k
12k = -24
k = -2.
Answer:
If the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 15
Standard Deviation, σ = 1
Sample size = 4
Total lifetime of 4 batteries = 40 hours
We are given that the distribution of lifetime is a bell shaped distribution that is a normal distribution.
Formula:

Standard error due to sampling:

We have to find the value of x such that the probability is 0.05
P(X > x) = 0.05
Calculation the value from standard normal z table, we have,
Hence, if the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.