Answer:
We want to construct a confidence interval at 99% of confidence, so then the significance level would be 
and the value of 
. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.
And if we find the critical value in the normal standard distribution or excel and we got:
And we can use the following excel code:
"=NORM.INV(0.005,0,1)"
Step-by-step explanation:
For this case we have the following info given:
We want to construct a confidence interval at 99% of confidence, so then the significance level would be and the value of . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.
And if we find the critical value in the normal standard distribution or excel and we got:
And we can use the following excel code:
"=NORM.INV(0.005,0,1)"
5^2+2[73-(-4x5)]
25+2[73-(-20)]
25+2[+93]
27+93=120
Answer:
sorry i would help if i new let me see if i can find it somewhere
Step-by-step explanation:
I don’t understand.
online school is hard
The 7 is in the thousands place, the 8 is in the hundreds place, the 5 is in the tens place, the 2 to the left side if re decimal point is in the ones place, the 2 to the right side of the decimal point is in the tenths place, the 0 is in the hundredths place, and the 9 is in the thousandths place.
