What is the equation of the graph below?°

PLS HELP ME...<br> Give five ordered pairs on the graph of y = -0.5x.

goblinko [34]

Answer:

(0,0) (-2,1) (-4,2) (-6,3) (-8,4)

Step-by-step explanation:

Hope this helps!

6 0

2 years ago

Ty collects coins from all over the world.He had 25 coins and received 14 on his birthday.What was the percent increase in coins

Ugo [173]

SOLUTION:

Amount added / Original amount × 100% = % increase

14 / 25 × 100 = 56%

FINAL ANSWER:

Therefore, the percentage increase in coins is 56%.

Hope this helps! :)

6 0

2 years ago

Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

3 years ago

Use deductive reasoning to show that the following procedure always produces the number 6. Procedure: Pick a number. Add 4 to th

Flauer [41]

Answer:

procedure always produces 6

Step-by-step explanation:

Let 'n' be the unknown number

Add 4 to the number : n+4

multiply the sum by 3.

multiply the sum n+4 by 3

$3(n+4) is 3n+12$

Now subtract 6, so we subtract 6 from 3n+12

$3n+12-6=3n+6$

finally decrease the difference by the tripe of the original number

triple of original number is 3n

$3n+6-3n= 6$

so the procedure always produces 6

5 0

3 years ago

Does anyone know a edulastic hack?

poizon [28]

Answer: The Pacing Method:

Use Edulastic to help convey weekly expectations and track student progress along the way

You can set up Edulastic to function as your check-in-tool with students, and Edulastic will help you in gathering student data during this process (#Edulasticforthewin!). This can help in estimating student participation grades and preparing reports to supervisors. It can also help with pacing and students staying on task.

When I was a high school science teacher I would structure “Check ins” with my students on written handouts that students had to present to me for my signature (upon meeting and discussing project updates, hearing feedback from me etc.). If I had access to Edulastic tools then, I could have instead coordinated these check ins digitally and privately using Edulastic. They could check-in on their own time, at home or at school. That makes things a heck of a lot more efficient than having students form a line waiting to talk to me at my desk! You can set this up to occur at the every other day mark, weekly mark, biweekly, or even monthly mark depending upon length and scope of a project in place.

Check out how this might look in Edulastic:

Step-by-step explanation:

4 0

3 years ago