we can see that the center is (-3, 3) and the radius is 9 units.
<h3 /><h3>
How to find the center and radius of the circle?</h3>
The general circle equation, for a circle with a center (a, b) and radius R is given by:
(x - a)^2 + (y - b)^2 = R^2
Here we have the equation:
x^2 + y^2 + 6x = 6y + 63
Let's complete squares:
x^2 + y^2 + 6x - 6y = 63
(x^2 + 6x) + (y^2 - 6y) = 63
(x^2 + 2*3x) + (y^2 - 2*3y) = 63
Now we can add and subtract 9, (two times) so we get:
(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63
(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2
(x + 3)^2 + (y - 3)^2 = 9^2
Comparing with the general circle equation, we can see that the center is (-3, 3) and the radius is 9 units.
If you want to learn more about circles:
brainly.com/question/1559324
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Let's solve your system by substitution.
−3x+y=−2;y=4x
Rewrite equations:
y=4x;−3x+y=−2
Step: Solvey=4xfor y:
y=4x
Step: Substitute4xforyin−3x+y=−2:
−3x+y=−2
−3x+4x=−2
x=−2(Simplify both sides of the equation)
Step: Substitute−2forxiny=4x:
y=4x
y=(4)(−2)
y=−8(Simplify both sides of the equation)
Answer:
x=−2 and y=−8
Answer:
It is four/4 I believe D.4
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
When you evaluate the problem you end up with 204100
Scientific Notation: 2.041 x 10^5
