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Wewaii [24]
3 years ago
11

in a race there are 15 Runners the trophies for the race are awarded to the races finish and 1st through 3rd place and how many

ways can first through third place be determined
Mathematics
2 answers:
vladimir1956 [14]3 years ago
6 0
There are 15 possibilities for first place, 14 for second, and 13 for third. 15 × 14 × 13 = 2730
lana [24]3 years ago
3 0

Answer:

<u>There are 2,730 ways that 1st, 2nd and 3rd place can be determined in the race</u>

Step-by-step explanation:

There are 15 (number of runners) possibilities to determine the 1st place

There are 14 possibilities (number of runners - 1) to determine the 2nd place

There are 13 possibilities (number of runners - 2) to determine the 3rd place

Number of ways that 1st, 2nd and 3rd place can be determined = 15 * 14 * 13

<u>Number of ways that 1st, 2nd and 3rd place can be determined = 2,730</u>

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Mark spends a total of $68.82 for 2 pairs of sneakers with the same cost. The sales tax is $5.32. Mark also uses a coupon for $3
shutvik [7]

Each pair of sneakers cost $33.25

Step-by-step explanation:

Given,

Total spent by Mark = $68.82

Sales tax = $5.32

Coupon used = $3.00

Price without sales tax = Total spent - sales tax

Price without sales tax = 68.82 - 5.32 = $63.50

As Mark used coupon, we will add this amount.

Amount of sneakers = Price without sales tax + Coupon used

Amount of sneakers = 63.50+3.00 = $66.50

As this is price of two sneakers, we will divide it by 2;

Cost of one sneaker = \frac{66.50}{2}=\$33.25

Each pair of sneakers cost $33.25

Keywords: subtraction, addition

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3 years ago
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Shtirlitz [24]

The coordinates of the pre-image of point F' is (-2, 4)

<h3>How to determine the coordinates of the pre-image of point F'?</h3>

On the given graph, the location of point F' is given as:

F' = (4, -2)

The rule of reflection is given as

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Mathematically, this is represented as

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So, we have

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Hence, the coordinates of the pre-image of point F' is (-2, 4)

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2 years ago
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Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

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