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galina1969 [7]
3 years ago
11

the measure of angle s = 30 degrees, the measure of arc RS = 84 degrees and line RU is tangent to the circle at R. Find m angle

U.

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

B. 12

Step-by-step explanation:

Paul [167]3 years ago
3 0
Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
</span>
Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0}  and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
<span />
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where
S is speed 
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t time 

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For the upstream trip:
S_{u}= \frac{d}{t_{u} }
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For the downstream trip:
S_{d}= \frac{d}{t_{d} }
S_{d}= \frac{d}{1.7} equation (2)

We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:
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Replacing (3) in (1):
S_{u}= \frac{d}{2}
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Solving for d in equation (2):
S_{d}= \frac{d}{1.7}
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Replacing (5) in (4):
S_{d}-2.5= \frac{d}{2}
S_{d}-2.5= \frac{1.7S_{d}}{2}
2(S_{d}-2.5)=1.7S_{d}
2S_{d}-5=1.7S_{d}
0.3S_{d}=5
S__{d}= \frac{5}{0.3}
S_{d}= \frac{50}{3} equation (6)

Replacing (6) in (5)
d=1.7S_{d}
d=1.7( \frac{50}{3} )
d= \frac{85}{3} miles

We can conclude that the boat travel \frac{85}{3}, which is approximately 28.3 miles, in one way.

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