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galina1969 [7]
3 years ago
11

the measure of angle s = 30 degrees, the measure of arc RS = 84 degrees and line RU is tangent to the circle at R. Find m angle

U.

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

B. 12

Step-by-step explanation:

Paul [167]3 years ago
3 0
Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
</span>
Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0}  and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
<span />
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Volgvan

Answer:

y = 24

Step-by-step explanation:

5/4y-18=y/2

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4 0
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Complete the equation of the line through (-9,-7) and (-6,-3)
Annette [7]

The equation of the line through (-9, -7) and (-6, -3) is y+3=\frac{4}{3}(x+6)

<u>Solution:</u>

Given, two points are (-9, -7) and (-6, -3)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

The slope of the line "m" is given as:

\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }

So slope of our line =\frac{-3-(-7)}{-6-(-9)}=\frac{-3+7}{-6+9}=\frac{4}{3}

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\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) \text { where } \mathrm{m} \text { is slope and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { is point on the line. }

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\text { Then, line equation } \rightarrow y-(-3)=\frac{4}{3}(x-(-6))

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Hence, the line equation is y+3=\frac{4}{3}(x+6)

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