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snow_tiger [21]

3 years ago

15

Legolas shoots 3 arrows at once from his bow. He has 177 arrows. How many times can Legolas shoot his bow before he needs more a

rrows?

1 answer:

Nataliya [291]3 years ago

3 0

Answer:

59

Step-by-step explanation:

3x=177

3x represents the # of arrow he can shoot at once every time

177 represents the total # of arrow he has

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Answer:

Equivalent expression:

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stich3 [128]

Answer: OPTION C

Step-by-step explanation:

There are some transformations for a function f(x). Some of them are shown below:

1. If $f(x)+k$ , the function is shifted up "k" units.

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3. If $f(x+k)$ , the function is shifted left "k" units.

4. If $f(x-k)$ , the function is shifted right "k" units.

In this case you know that the function "g" is the transformation of the function "f".

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And the function "g" intersects the y-axis at:

$y=-2$

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This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

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$L_y=10+10\lambda y=0\implies1+\lambda y=0$

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$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

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Rama09 [41]

See attachment for math work and answer.

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