Let the cost of 1 notebook be x and the cost of 1 binder be y.
4 notebooks and 3 binders would cost 23.5
Therefore, 4x + 3y = 23.5 (1)
7 notebooks and 6 binders would cost 44.5
Therefore, 7x + 6y = 44.5 (2)
Multiply the first equation by 2.
8x + 6y = 47 (3)
(3) - (2) gives
x = 2.5
Substitute the value of x in (1), we get,
4(2.5) + 3y = 23.5
10 + 3y = 23.5
3y = 23.5 - 10
3y = 13.5
y = 13.5/3
y = 4.5
Hence, cost of 5 notebooks and 3 binders is:
5x + 3y = 5(2.5) + 3(4.5)
= 12.5 + 13.5
= 26
Hence, cost of 5 notebooks and 3 binders is $26.
Answer:
4x^2+11x+23 r53
Step-by-step explanation:
4x^3-3x^2+x+7 / x-2
2 | 4 -3 1 7
8 22 46
___________
4 11 23 53
This means 4x^2+11x+23 with a remainder of 53
Answer:
28
Step-by-step explanation:
4*7= 28
when there is a variable (letter next to the number) next to the number like 4a it means 4 multiplied by a. since a is 7, 4 multiplied by 7 is 28.
Answer:

» Collect like terms, r terms on the left hand side by subtracting r from both sides and adding st to both sides

» On the left hand side, factorise out r

We have (2/3)÷5 = 2/15 advertisments for 1 page;
Then, we have 98 · (2/15) = 12.2(6) advertisments for 98 pages;
The nearest whole page is 12.