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Veronika [31]
4 years ago
10

1) Using only astronomical data, calculate the speed of the planet Venus in its essentially circular orbit around the sun.

Physics
1 answer:
miss Akunina [59]4 years ago
6 0

Answer:

1)     v_orbit = 3.49*10^4 m/s

2)    F = 5.51*10^22 N

Explanation:

1) In order to calculate the speed of Venus in its orbit, you use the following formula:

v_{orbit}=\sqrt{\frac{GM_s}{R}}         (1)

v_orbit: speed of Venus = ?

G: Cavendish's constant = 6.674*10^-11.m^3kg^-1s^-2

Ms: mass of the sun = 1.98*10^30 kg

R: distance between the center of Sun and the center of Venus = 1.08*10^11m

You replace the values of the parameters in the equation (1):

v_{orbit}=\sqrt{\frac{(6.674*10^{-11}m^3kg^{-1}s^{-2})(1.98*10^{30})}{1.08*10^{11}m}}\\\\v_{orbit}=3.49*10^4\frac{m}{s}

The speed of Venus in its orbit around the Sun is 3.49*10^4 m/s

2) The force is given by the following formula:

F=G\frac{M_vM_s}{R^2}

Ms: mass of Venus = 4.87*10^24 kg

F=(6.674*10^{-11}m^3kg^{-1}s-2})\frac{(4.87*10^{24}kg)(1.98*10^{30}kg)}{(1.08*10^{11}m)^2}\\\\F=5.51*10^{22}N

The Sun exertes on Venus a force of 5.51*10^22 N

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A gas is compressed from 600cm3 to 200cm3 at a constant pressure of 450kPa . At the same time, 100J of heat energy is transferre
Paraphin [41]

Answer: 80J

Explanation:

According to the first principle of thermodynamics:  

<em>"Energy is not created, nor destroyed, but it is conserved."  </em>

Then this priciple (also called Law) relates the work and the transferred heat exchanged in a system through the internal energy U, which is neither created nor destroyed, it is only transformed. So, in this especific case of the compressed gas:

\Delta U=Q+W  (1)

Where:

\Delta U is the variation in the internal (thermal) energy of the system (the value we want to find)

Q=-100J is the heat transferred out of the gas (that is why it is negative)

W is the work is done on the gas (as the gas is compressed, the work done on the gas must be considered positive )

On the other hand, the work done on the gas is given by:

W=-P \Delta V  (2)

Where:

P=450kPa=450(10)^{3}Pa is the constant pressure of the gas

\Delta V=V_{f}-V_{i} is the variation in volume of the gas

In this case the initial volume is V_{i}=600{cm}^{3}=600(10)^{-6}m^{3} and the final volume is V_{f}=200{cm}^{3}=200(10)^{-6}m^{3}.

This means:

\Delta V=200(10)^{-6}m^{3}-600(10)^{-6}m^{3}=-400(10)^{-6}m^{3}  (3)

Substituting (3) in (2):

W=-450(10)^{3}Pa(-400(10)^{-6}m^{3})  (4)

W=180J  (5)

Substituting (5) in (1):

\Delta U=-100J+180J  (6)

Finally:

\Delta U=80J  This is the change in thermal energy in the compression process.

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A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne
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Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

W_x = 500 cos37

W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

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