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Liula [17]
3 years ago
9

Why do atoms of element have neutral charge?

Physics
2 answers:
nasty-shy [4]3 years ago
6 0
 because the positive and negative charge is equal the element produces a neutral charge.

SVEN [57.7K]3 years ago
3 0
The number of Protons in the nucleus is equal to the number of electrons orbiting the same nucleus.

hope that helps/makes sense
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Could someone summarize these into a paragraph? i'll give brainliest<br> DUE TODAY!!
slamgirl [31]

Answer:

I can't see the picture

Explanation:

Im sorry can you right whats on the picture down in the comments plz.

6 0
3 years ago
Read 2 more answers
Stacey runs around a 400 meter track 2 times in 5 minutes. How does her displacement differ from her distance? *
liq [111]

Answer:

Distance is 800 m and Displacement is 0 m

Explanation:

Total Distance

= 400(2)

= <u>800</u><u> </u><u>m</u>

Total Displacement

= <u>0</u><u> </u><u>m</u> since she returns to the same spot

6 0
3 years ago
Vector has a magnitude of 6.0 m and points 30° north of east. Vector has a magnitude of 4.0 m and points 30° east of north. The
Brut [27]

Answer:

The resultant vector is \vec R = \vec A + \vec B = 7.196\,i + 6.464\,j.

Explanation:

First, each vector is determined in terms of absolute coordinates:

6-meter vector with direction: 30º north of east.

\vec A = (6\,m)\cdot (\cos30^{\circ} \,i + \sin 30^{\circ}\,j)

\vec A = 5.196\,i + 3\,j

4-meter vector with direction: 30º east of north.

\vec B = (4\,m)\cdot (\cos 60^{\circ}\,i + \sin 60^{\circ}\,j)

\vec B = 2\,i + 3.464\,j

The resultant vector is obtaining by sum of components:

\vec R = \vec A + \vec B = 7.196\,i + 6.464\,j

The resultant vector is \vec R = \vec A + \vec B = 7.196\,i + 6.464\,j.

5 0
4 years ago
How dose an exam question outed from text book​
Verizon [17]

Answer:

In which school you are???

Explanation:

4 0
3 years ago
A merry go round exerts a force of 1000 N on a rider on the
SVEN [57.7K]

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r

Where;

m = The mass of the person

v = The velocity of the person

F_c = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

F_c = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

3 0
3 years ago
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