Question

A proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton. Determine the magnitude of the electric field at the location of the proton hethe magitude of the electric Select the correct answer a. 10- N/C b. 10-3N/c c. 10-4N/c d 10 N/C e 10-6N/c

Answer 1

Answer:

Electric field, $E=10^{-7}\ N/C$

Explanation:

It is given that, a proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton such that,

$qE=mg$

$E=\dfrac{mg}{q}$

$E=\dfrac{1.67\times 10^{-27}\times 9.8}{1.6\times 10^{-19}}$

$E=1.02\times 10^{-7}\ N/C$

or

$E=10^{-7}\ N/C$

So, the magnitude of electric field at the location of the proton is $10^{-7}\ N/C$. Hence, this is the required solution.