AD = BC ----> Parallel lines
AC = AC -----> Reflexive property
<A = <C -----> Congruent angles
<D = <B -----> Congruent angles
The tank with Chemical X "takes up" a space of 25ft³. Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume. The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:

To find the volume of a cylinder, we find the base area and multiply by the height. We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:

We would now divide both sides by 3 2/10:

This is the same as:

So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
we are asked to write an expression that uses partial products to multiply 8 and 64. In this case, we can break 8 into 2 x4 and 64 into 8x8. In this case, multiplying these factors equal to 512. Any factors will do actually since it will yield the same product.
Answer:
63%
Step-by-step explanation:
This is a problem of conditional probability.
The two events that are given are:
- Car stuck in the snow - Let it be event S. P(S) = 70% = 0.70
- Require a tow truck - Let it be event T.
We have to find the probability of being stuck in the snow AND requiring a tow truck which can be given as P(S and T)
We are also given the conditional probability, which is P(T | S) = 90% = 0.90
Using the given formula for our case we can modify the formula as:


Therefore, there is 63% (0.63) chance that you will get stuck in the snow with your car AND require a tow truck to pull you out