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olya-2409 [2.1K]

3 years ago

15

Definition of Line segment

1 answer:

klemol [59]3 years ago

3 0

The definition of a line segment is a line that will never end

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Write an equation in slope-intercept form of<br> the line that passes through (-6,4) and<br> (-1,2).

xz_007 [3.2K]

Answer:

Step-by-step explanation:

(-6 , 4) & (-1 , 2)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}$

m = -2/5 & (-6 , 4)

y -y1 = m(x -x1)

$y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}$

6 0

3 years ago

What is the domain and range of the relation [(1, -8), (-7,8), (-3, 7). (-3, -5]?

Nadusha1986 [10]

Step-by-step explanation:

domain = {-7, -3, 1}

range ={-8, -5, 7, 8}

6 0

3 years ago

Each vertical cross-section of the triangular

Blizzard [7]

Answer:

The vertical height is $h=3\ units$

Step-by-step explanation:

we know that

In the right triangle ABC

see the attached figure

To find the height h apply the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

we have

$c=AB=3\sqrt{2}\ units$

$a=BC=6/2=3\ units$

$b=AC=h\ units$

substitute

$(3\sqrt{2})^{2}=3^{2}+h^{2}$

$18=9+h^{2}$

$h^{2}=18-9=9$

$h=3\ units$

3 0

3 years ago

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11. El 9 de enero venden a crédito a Stan Lee Co las siguientes mercancías: 4

Allushta [10]

A AS

Step-by-step explanation:

7 0

3 years ago

If f(x)=√2x+3/6x-5, then f(-1/2)=

denis23 [38]

answere=-1

this is the answere and the explanation.

8 0

3 years ago