One of the answers is the letter C parallelogram
Answer:
No, the expression is not linear because the highest power of x is 2.
Answer:
![\dfrac{\sqrt[12]{55296}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B12%5D%7B55296%7D%7D%7B2%7D)
Step-by-step explanation:
Rationalize the denominator, then use a common root for the numerator.
![\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\\\\=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\cdot\dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{2^{\frac{1}{4}+\frac{2}{3}}3^{\frac{1}{4}}}{2}\\\\=\dfrac{2^{\frac{11}{12}}3^{\frac{3}{12}}}{2}=\dfrac{\sqrt[12]{2^{11}3^{3}}}{2}\\\\=\dfrac{\sqrt[12]{55296}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B4%5D%7B6%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cdfrac%7B%282%5Ccdot%203%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%282%5Ccdot%203%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5Ccdot%5Cdfrac%7B2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7B2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%3D%5Cdfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B2%7D%7B3%7D%7D3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D3%5E%7B%5Cfrac%7B3%7D%7B12%7D%7D%7D%7B2%7D%3D%5Cdfrac%7B%5Csqrt%5B12%5D%7B2%5E%7B11%7D3%5E%7B3%7D%7D%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B12%5D%7B55296%7D%7D%7B2%7D)
We want to find the value that makes

To find it we must look at the standard normal table, using the complementary cumulative table we find that

Then, using the z-score we can find the minimum score needed, remember that

Where
σ = standard deviation
μ = mean
And in our example, x = minimum score needed, therefore

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.