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Alchen [17]
3 years ago
15

What is average of 65& 30

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0
47.5 is correct answer
Dmitry_Shevchenko [17]3 years ago
5 0
The average of 65 and 30 is 47.5.

Here are the calculations:

65+30= 95
95/2= 47.5 (95 divided by 2)

Have a nice day/night and I hope this helped!
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In a - 3 = 15, the value of a HAS to be 18.

In a - 3 is greater than or equal to 15, the value of a is any value that is 18 or higher.
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I need help simplifying this expression<br><br> 9•(7-4)^2+9
marshall27 [118]

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90

Step-by-step explanation:

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Consider two countries, A and B, whose respective industries produce goods A and B. Total world output of the good is given by Q
castortr0y [4]

Answer: hello your question is poorly written attached below is the complete question

answer :

a) 31.5

b) 24.5

Step-by-step explanation:

Total world output of good given ( Q ) = qA + qB

world demand ( P ) = 100 - Q

cost function for country A = cA (qA) = 8qA

cost function of country B = cB(qB) = 3qB

total world emission = 0.5Q

emission per unit good = 0.5

<u>a) Determine total world emissions when both countries compete in a Cournot fashion</u>

Q = 63

therefore Total world emission = 0.5 ( Q )

                                                    = 0.5 ( 63 ) = 31.5

attached below is the detailed solution

<u>b) Determine the total world emissions after Country A enacts a carbon tax</u>

Q = 49

Therefore Total world emission after tax = 0.5 ( Q )

                                                                    = 0.5 ( 49 ) = 24.5

attached below is the detailed solution

5 0
2 years ago
A golfer keeps track of his score for playing nine holes of golf​ (half a normal golf​ round). His mean score is 8080 with a sta
solniwko [45]

Answer:

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 11\sqrt2 respectively.

Step-by-step explanation:

Given that,

For the first 9 holes X:

E(X) = 80

SD(X)=13

For the second 9 holes Y:

E(Y) = 80

SD(Y)=13

For the sum W=X+Y, the following properties holds for means , variance and standard deviation :

E(W)=E(X)+E(Y)

     and

V(W)=V(X)+V(Y)

⇒SD²(W)=SD²(X)+SD²(Y)        [ Variance = (standard deviation)²]

\Rightarrow SD(W)=\sqrt{SD^2(X)+SD^2(Y)}

∴E(W)=E(X)+E(Y) = 80 +80=160

            and

∴SD(W)=\sqrt{SD^2(X)+SD^2(Y)}

              =\sqrt{11^2+11^2}

               =\sqrt{2.11^2}

               =11\sqrt2

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 11\sqrt2 respectively.

                                               

4 0
3 years ago
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