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4 years ago

Evaluate the following expression. You should do this problem without a calculator. e^ln 6

2 answers:

8 0

$\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \boxed{a^{log_a x}=x}\\\\
-------------------------------\\\\
e^{ln(6)}\implies \stackrel{\textit{base of logarithm is the same as base of expression}}{e^{log_e(6)}}\implies 6$

katrin2010 [14]4 years ago

5 0

Answer:

Step-by-step explanation:

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Answer:

3 liters

Step-by-step explanation:

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3 years ago

If u have 8 and u add 7 more then u multiple it bye 12 how much will u have in total

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3 years ago

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What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

Part a: The height of the ball when t = 2 seconds:

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

Part b: The height of the ball when t = 4 seconds:

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$

Simplifying the terms, we get;

$h(4)=-256+320+4$

$h(4)=68$

Thus, the height of the ball after 4 seconds is 68 feet.

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4 years ago