A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
So for this i would always drop the decimal from the number so it will be 796 ÷ 5 which would be 159.2 so the was two numbers in the original problem over from the decimal would be put back in the answer. so you would put the decimal in over two times so the answer will be 1.592
This question is Incomplete
Complete Question
Rectangle ABCD has a length represented by the expression 2x – 3, and a width represented by the expression 4x + 5. Rectangle PQRS has a length represented by the expression x – 1, and a width represented by the expression 3x + 2. Which Expression can be used to represent the difference in the perimeter of Rectangle ABCD and Rectangle PQRS?
a) 2x + 1
b) 4x + 2
c) 4x + 6
d) 20x + 6
Answer:
b) 4x + 2
Step-by-step explanation:
The Formula for the Perimeter of a Rectangle = 2(L + W)
= 2L + 2W
Hence:
For rectangle ABCD
Length = 2x - 3
Width = 4x + 5
Hence, the Perimeter is :
P = 2L + 2W
P = 2(2x - 3) + 2(4x + 5)
P = 4x - 6 + 8x + 10
P = 4x + 8x -6 + 10
P = 12x + 4
For Rectangle PQRS
Length = x - 1
Width = 3x + 2
Hence, the Perimeter is :
P = 2L + 2W
P = 2(x - 1) + 2(3x + 2)
P = 2x - 2 + 6x + 4
P = 2x + 6x - 2 + 4
P = 8x + 2
The Expression that can be used to represent the difference in the perimeter of Rectangle ABCD and Rectangle PQRS is
Perimeter of Rectangle ABCD - Perimeter of Rectangle PQRS
(12x + 4) - (8x + 2)
12x + 4 - 8x - 2
12x - 8x +4 -2
4x + 2
Option b) 4x + 2 is the correct option.
Answer:
= 380
Step-by-step explanation:
(38*55) + (-45*38)
(2090) + (-1710)
2090 - 1710
= 380
Answer:
40
Step-by-step explanation:
90/8=11.25 (1 flapjack)
11.25x40=450