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Advocard [28]
3 years ago
5

Can someone help me with this question please?.

Mathematics
1 answer:
Taya2010 [7]3 years ago
3 0
Answer: I think its n-12
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Help please i don’t know how to do it
nekit [7.7K]

Answer:

x + 3y = 15

Step-by-step explanation:

Line is passing through the points (3, \:4) = (x_1,\:y_1)\:and\: (9, 2)=(x_2,\:y_2)

Slope of line (m)= (2 - 4)/(9 - 3) = -2/6 = -1/3

Equation of line in point-slope form is given as:

y-y_1 =m(x-x_1)

Plugging the values of x_1,\: y_1\: and \: m in the above equation we find:

y-4 =-\frac{1}{3}(x-3)

\implies 3y-12 =-x+3

\implies x+ 3y =12+3

\implies \huge {\orange{\boxed{x+ 3y = 15}}}

This is the required equation of line in the form \red{\bold{ax + by = c}}

5 0
2 years ago
11) Determine if the following numbers are<br> prime, composite or neither.<br> 13
harina [27]

Answer:

13 is Prime

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can any math genius help me with this
vovangra [49]

<em>Here's</em><em> </em><em>my</em><em> </em><em>working</em><em> </em><em>for</em><em> </em><em>1</em><em>)</em><em> </em><em>You</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>exterior</em><em> </em><em>angle</em><em>,</em><em> </em><em>then</em><em> </em><em>divide</em><em> </em><em>by</em><em> </em><em>360</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>sides</em><em>:</em>

<em>Applying</em><em> </em><em>these</em><em> </em><em>steps</em><em> </em><em>:</em><em> </em>

180 (Interior Angles) - 162 = 18 (Exterior angle)

360 ÷ 18 is<em> </em><em>20</em><em> </em><em>sides</em><em> </em>

<em>For</em><em> </em><em>2</em><em>)</em>

<em>Its</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>method</em><em>,</em><em> </em><em>so</em><em> </em><em>apply</em><em> </em><em>the</em><em> </em><em>steps</em><em>:</em>

<em>180</em><em> </em><em>-</em><em> </em><em>175</em><em> </em><em>=</em><em> </em><em>5</em>

<em>360</em><em> </em><em>÷</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>72</em><em> </em><em>sides</em><em> </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>!</em><em> </em><em>:</em><em>)</em><em> </em>

8 0
3 years ago
e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv
Naddika [18.5K]

Answer:

The answer is \{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}

Step-by-step explanation:

Remember that a reflexive relation R\subset \mathcal{P}(X), where \mathcal{P}(X) is the power set of X, is one which conteins the ordered pairs of the form (a,a), for a\in X.

So, As the reflexive and transitive closure of R (that we will denote by \overline{R}) is in particular reflexive, we must add to R  the elements \{(1,1) , (2,2),(3,3),(4,4) \}

A transitive relation R is one in which if the pair (a,b) and the pair (b,c) are in there, then the pair (a,c) must be there too.

So, to complete the relation R to be reflexive and transitive we must add the pair (1,3) (because (1,2),(2,3) are in R), the pair (2,4), and the pair (1,4) because we added the pair (2,4).

Therfore we have that \overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}.

6 0
3 years ago
The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre
Rasek [7]

Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

f(x)=b+mx

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

  • At 104 chirps per minute, the temperature is 63 ºF.
  • At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and  y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

  • Find the slope:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}

  • Find the equation:

81=\frac{1}{4}\cdot 104+b

Solving for b

b=81-\frac{1}{4} (176)=37

Therefore, the linear function is

y=\frac{1}{4} \cdot x+37

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (124)+37=68

For 68 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (68)+37=54

6 0
3 years ago
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