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Rzqust [24]
3 years ago
15

Find the value of the following expression:

Mathematics
2 answers:
Ket [755]3 years ago
7 0
(2^8 . 5^-5 . 19^0)^-2

using PEMDAS

this = (2^8 * 1/5^5 * 1)^-2


=  (5^5 / 2^8)^2

= 5^10 / 2^16
Deffense [45]3 years ago
5 0

Answer:

2^8 . 5^-5 . 19^0)^-2

using PEMDAS

this = (2^8 * 1/5^5 * 1)^-2

=  (5^5 / 2^8)^2

= 5^10 / 2^16

Step-by-step explanation:

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Solve the system of equations 5x-2y=88 3x+4y=58 show all work
diamong [38]
The given equations are:

5x - 2y = 88
3x + 4y =  58

Multiplying the 1st equation by 2, we get the new set of equations as:

10x - 4y = 176
3x + 4y = 58

Adding the two equations, we get:

10x - 4y + 3x + 4y = 176 + 58
13x =234
x =  18

Using the value of x in 1st equation, we get:

5(18) - 2y = 88
- 2y = 88 -5(18)
-2y = -2
y = 1

So, the solution of the equation is (18, 1)

6 0
3 years ago
Read 2 more answers
The stores below each have the same snowboard for an original price of $189.59. At which store can you get the snowboard for the
Rama09 [41]

Answer: D.

You can get the lowest price at Store C

7 0
3 years ago
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

  • \angle DIH\cong \angle EGH as alternate interior angles;
  • \angle DHI\cong \angle GHE as vertical angles;
  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
3 years ago
Carmen ran 2 laps around the track in 6 minutes. What are the unit rates in laps per minute and minutes per lap?
Rudiy27
6/2 = 3 (minutes per lap)
3 0
3 years ago
Question 2
evablogger [386]

The domain of the function is x ≤ 6.88

The domain of the function is y ≤ 20

<h3>Domain and Range</h3>
  • These are input and output values for which the function exists

Given the function of x expressed as:

y = 3.5x + 2.8

The domain occurs at the point where 3.5x + 2.8 ≤ 20

3.5x ≤ 20 - 2.8

3.5x ≤ 17.2

x ≤ 6.88 - Domain

This given the domain of the function.

The range of the function is the point where y ≤ 20

Learn more on domain and range here: brainly.com/question/2264373

7 0
2 years ago
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