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Anvisha [2.4K]
3 years ago
9

A recipe that makes 6 servings calls for 1 1/5 cups of juice.

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0
So 6 servings is 1 1/5 cups
so 6=1 1/5
1 1/5=6/5
so 6=6/5
divide both sides by 6
1 serving=1/5 cup or B
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What is meant mathematically when we say we have an "even" or "odd" function?
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I a function is even the leading term will have an even exponent. If a function is odd than the leading terms exponent is odd.

an even function has a parabola looking graph, while an odd function has min and max graph

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3 years ago
What is the following product
frosja888 [35]
I would pick C sorry if it’s wrong
3 0
3 years ago
Read 2 more answers
Write the equation of the line in point-slope form that has slope 3 and passes through (2, -5)
Fynjy0 [20]

Answer:

y = 3x - 11      

Step-by-step explanation:

Step 1:

y = mx + b          Slope Intercept Form

Step 2:

y = 3x + b        Input Slope

Step 3:

- 5 = 3 ( 2 ) + b        Input x and y values

Step 4:

- 5 = 6 + b          Multiply

Step 5:

- 11 = b        Subtract 6 on both sides

Answer:

y = 3x - 11      

Hope This Helps :)

5 0
3 years ago
Help please!!!!! What is the answer (algebra)
zaharov [31]

Answer:

girlllllllll let me work it out lol

Step-by-step explanation:

8 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
kompoz [17]

a.

f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}

is a proper joint density function if, over its support, f is non-negative and the integral of f is 1. The first condition is easily met as long as C\ge0. To meet the second condition, we require

\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}

b. Find the marginal joint density of X and Y by integrating the joint density with respect to z:

f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz

\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

Then

\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy

\approx\boxed{0.12886}

c. This probability can be found by simply integrating the joint density:

\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

\approx\boxed{0.012262}

7 0
3 years ago
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