Determine the relationship described in each table. Please help me
1 answer:
I graphed the given points and based on my graph.
<span> x y </span>→ EXPONENTIAL<span><span>
</span> <span> -2 21
</span><span> 1 4
</span><span> 0 1
</span><span> 1 0
</span></span><span> x y </span>→ LINEAR<span><span>
</span> <span> -2 6
</span> <span> -1 -2
</span><span> 0 2
</span><span> 1 6
</span></span>
<span> x y </span>→ QUADRATIC<span><span>
</span> <span> -2 12
</span> <span> -1 -2
</span><span> 0 -8
</span><span> 1 -6
</span></span><span> <span><span> x y </span></span></span>→ EXPONENTIAL<span><span><span>
</span> <span> -2 16
</span> <span> -1 8
</span><span> 0 4
</span><span> 1 2
LINEAR FUNCTIONS always maintain a constant slope. In the above linear function, the slope is 4.
EXPONENTIAL and QUADRATIC FUNCTIONS have different slope in every point.
Exponential functions can be identified by the immediate increase or decrease in the value of y resulting to a minimal increase or decrease in the value of x.
Quadratic functions can be identified as such due to the similar points it has after having the vertex.
</span></span></span>
<span> x y </span>→ EXPONENTIAL<span><span>
</span> <span> -2 21
</span><span> 1 4
</span><span> 0 1
</span><span> 1 0
</span></span><span> x y </span>→ LINEAR<span><span>
</span> <span> -2 6
</span> <span> -1 -2
</span><span> 0 2
</span><span> 1 6
</span></span>
<span> x y </span>→ QUADRATIC<span><span>
</span> <span> -2 12
</span> <span> -1 -2
</span><span> 0 -8
</span><span> 1 -6
</span></span><span> <span><span> x y </span></span></span>→ EXPONENTIAL<span><span><span>
</span> <span> -2 16
</span> <span> -1 8
</span><span> 0 4
</span><span> 1 2
LINEAR FUNCTIONS always maintain a constant slope. In the above linear function, the slope is 4.
EXPONENTIAL and QUADRATIC FUNCTIONS have different slope in every point.
Exponential functions can be identified by the immediate increase or decrease in the value of y resulting to a minimal increase or decrease in the value of x.
Quadratic functions can be identified as such due to the similar points it has after having the vertex.
</span></span></span>
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<em>Well, that doesn't seem to be parallel. This is called one solution answer. Both graphs intercept at (2,0). There are no linear graphs that intercept at (2,-2) except for y = x-2 so there are no graphs with (2,-2) that are parallel to the equation y = -5x/2+5 </em>