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harkovskaia [24]
3 years ago
10

A computer system requires that passwords contain at least one digit. if eight characters are generated at random, and each is e

qually likely to be any of the 26 letters or 10 digits, what is the probability that a valid password will be generated?
Mathematics
1 answer:
KIM [24]3 years ago
6 0
Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters]  =  2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8

The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598
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