-3(x + 4y) + 2(x – 2y) + (3x -5y)
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The solution to the system of equations is (-1, 1) and (1, -1)
<h3>How to determine the solution to the system of equations?</h3>The system of equations is given as:
x^3 + x^2y + xy^2 + y^3 = 0
x^2 + 4y^2 = 5
The equations in the above system of equations are nonlinear equations.
The best way to a system of equations that are nonlinear equations is by the use of graphs
So, we start by plotting the graphs of the equations in the system of equations given as x^3 + x^2y + xy^2 + y^3 = 0 and x^2 + 4y^2 = 5
See attachment for the graph
The point of intersection represents the solution
From the attached graph, the points of intersection of the equations are
(-1, 1) and (1, -1)
Hence, the solution to the system of equations is (-1, 1) and (1, -1)
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