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dolphi86 [110]
3 years ago
9

Translate the sentence into an inequality.

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

6\,b-9\leq -16

Step-by-step explanation:

SInce the sentence reads "Nine subtracted from..." start by creating the quantity that 9 would be subtracted from, to make the expression more obvious. So let's begin by making the product of 6 times a "number" (unknown value) and use for the unknown the letter "b" as requested:

6\,b. Now proceed to subtract 9 from this expression:

6\,b-9

The sentence now continues saying that this expression is at most -16. So we understand that the quantity we created above has to be smaller or at most equal to -16. Therefore, we use the inequality symbol "\leq" to complete the sentence in mathematical terms:

6\,b-9\leq -16

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Explanation:
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(-3/8) + (5/8) = (-3 + 5) / 8 = 2/8 ; 

→ 2/8 = (2÷2) / (8÷2) = 1/4 ;  → which is:  Answer choice:  [C]:  " 1/4" .
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A chain has a ribbon tied to it every 2/3 foot. If the chain is 10 2/3 feet long, how many ribbons are tied to the chain??
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Answer:

16 ribbons

Step-by-step explanation:

Given the length of the chain as 10\frac{2}{3} and there is a ribbon tied to it every \frac{2}{3}, we can take the total length of the chain and divide by the measure of \frac{2}{3}:

10\frac{2}{3}=\frac{32}{3}

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3 years ago
The silver town people went to a fancy restaurant after the big event Grammy gave the sever a 15$ tip if she was 20% cost of din
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Oliver invested $970 in an account paying an interest rate of 7 1/2 % compounded continuously. Carson invested $970 in an accoun
hjlf

Answer:

0.50 or about half a year longer.

Step-by-step explanation:

We can write an equation to model bot investments.

Oliver invested $970 in an account paying an interest rate of 7.5% compounded continuously.

Recall that continuous compound is given by the equation:

A = Pe^{rt}

Where <em>A</em> is the amount afterwards, <em>P</em> is the principal amount, <em>r</em> is the rate, and <em>t</em> is the time in years.

Since the initial investment is $970 at a rate of 7.5%:

A = 970e^{0.075t}

Carson invested $970 in an account paying an interest rate of 7.375% compounded annually.

Recall that compound interest is given by the equation:

\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the amount afterwards, <em>P</em> is the principal amount, <em>r</em> is the rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the time in years.

Since the initial investment is $970 at a rate of 7.375% compounded annually:

\displaystyle A = 970\left(1+\frac{0.07375}{1}\right)^{(1)t}=970(1.07375)^t

When Oliver's money doubles, he will have $1,940 afterwards. Hence:

1940= 970e^{0.075t}

Solve for <em>t: </em>

\displaystyle 2 = e^{0.075t}

Take the natural log of both sides:

\ln\left (2\right) = \ln\left(e^{0.075t}\right)

Simplify:

\ln(2) = 0.075t\Rightarrow \displaystyle t = \frac{\ln(2)}{0.075}\text{ years}

When Carson's money doubles, he will have $1,940 afterwards. Hence:

\displaystyle 1940=970(1.07375)^t

Solve for <em>t: </em>

2=(1.07375)^t

Take the natural log of both sides:

\ln(2)=\ln\left((1.07375)^t\right)

Simplify:

\ln(2)=t\ln\left((1.07375)\right)

Hence:

\displaystyle t = \frac{\ln(2)}{\ln(1.07375)}

Then it will take Carson's money:

\displaystyle \Delta t = \frac{\ln(2)}{\ln(1.07375)}-\frac{\ln(2)}{0.075}=0.4991\approx 0.50

About 0.50 or half a year longer to double than Oliver's money.

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