Answer:
a) r = 0.974
b) Critical value = 0.602
Step-by-step explanation:
Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below
Test A | 64 48 51 59 60 43 41 42 35 50 45
Test B | 91 68 80 92 91 67 65 67 56 78 71
To find - (a) What is the value of the linear coefficient r ?
(b) Assuming a 0.05 level of significance, what is the critical value ?
Proof -
A)
r = 0.974
B)
Critical Values for the Correlation Coefficient
n alpha = .05 alpha = .01
4 0.95 0.99
5 0.878 0.959
6 0.811 0.917
7 0.754 0.875
8 0.707 0.834
9 0.666 0.798
10 0.632 0.765
11 0.602 0.735
12 0.576 0.708
13 0.553 0.684
14 0.532 0.661
So,
Critical r = 0.602 for n = 11 and alpha = 0.05
Answer:
A. {4,3}
Step-by-step explanation:
x -2y = -2
y = - 3x +15
x - 2(-3x+15) = -2
x +6x - 30 = -2
7x = 28
x = 4
y = - 3x +15 = - 3*4 + 15 = -12 + 15 = 3
{4,3}
5/8 would be the simplest form for 10/16 .
The sale price is 255 dollars.
To get the answer you find out that ten percent of 340 is 34 dollars. then you double the percentage which brings you to 68 dollars. but you still have 5 percent left over. Half of the ten percent is 17 dollars. finally you add 68 plus 17 which gives you 84 dollars. Lastly subtract 84 dollars from 340 which gives you 255
Hope this helps! :)