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4 years ago

What is 5/8 + 3/4 because I am doing fractions right know

2 answers:

4 0

$\frac{5}{8} + \frac{3}{4} =$

So, $\frac{5}{8} + \frac{3}{4} * \frac{2}{2} = \frac{5}{8} + \frac{6}{8} = \frac{11}{8}$

Simplified as mixed number equals to $1 \frac{3}{8}$

(Keep in mind that the LCM was 8.)

Sergio [31]4 years ago

4 0

$\frac{5}{8} + \frac{2}{4}$

Denominators should be of same numbers

$\frac{5}{8} + \frac{3~multiply~by~2}{4~multiply~by~2}$

$\frac{5}{8} + \frac{6}{8}$

$\frac{11}{8}$

$1\frac{3}{8}$

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Iff (x) = 3x + 2 and g(x) = x? – x, find the value.<br> =<br> f (4)

earnstyle [38]

-4

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5 0

3 years ago

Use the equation k = x÷ y to find the constant of proportionality for the set of values

Lubov Fominskaja [6]

The constant of proportionality is 1/3

and three more values are

x 1 2 3 4 5

y 3 6 9 12 15

<h3>Variation</h3>

From the question, we are to determine the constant of proportionality

The given equation is

k = x ÷ y

From the given information,

When x = 1, y = 3

∴ k = 1 ÷ 3

k = 1/3

Thus, the constant of proportionality is 1/3

Now, we will determine the values of y for the values x = 3, x = 4, and x = 5

Since

k = x ÷ y

Then,

y = x ÷ k

When x = 3

y = 3 ÷ 1/3

y = 3 × 3

y = 9

When x = 4

y = 4 ÷ 1/3

y = 4 × 3

y = 12

When x = 5

y = 5 ÷ 1/3

y = 5 × 3

y = 15

Hence, the constant of proportionality is 1/3

and three more values are

x 1 2 3 4 5

y 3 6 9 12 15

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3 0

3 years ago

find the area of the shaded region of the radius is 9<br> Did I get the answer right

crimeas [40]

Answer:69.66

r=9 so diameter is 18, and the shape being a square you do 18 x 18 = 324

now the circles area is 254.34 now find the difference... and it is 69.66

Step-by-step explanation:

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3 years ago

One concern of a gambler is that she will go broke before achieving her first win. Suppose that she plays a game in which the pr

Ray Of Light [21]

Answer:

The probability that she wins exactly once before she loses her initial capital is 0.243.

Step-by-step explanation:

The gambler commences with $30, i.e. she played 3 games.

Let <em>X</em> = number of games won by the gambler.

The probability of winning a game is, <em>p</em> = 0.10.

The random variable <em>X</em> follows a Binomial distribution, with probability mass function:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2,...$

Compute the probability of exactly one winning as follows:

$P(X=1)={3\choose 1}(0.10)^{1}(1-0.10)^{3-1}\\=3\times0.10\times0.81\\=0.243$

Thus, the probability that she wins exactly once before she loses her initial capital is 0.243.

4 0

4 years ago

What is the solution to the equation?

AleksandrR [38]

Solution of the equation: $x=6\frac{1}{2}$

Step-by-step explanation:

The equation that we have to solve in this problem is:

$13\frac{3}{4}+x=7\frac{1}{4}$

The first step to do is to rewrite the mixed fractions as improper fractions. We have:

$13\frac{3}{4}=\frac{13\cdot 4+3}{4}=\frac{52+3}{4}=\frac{55}{4}$

And

$7\frac{1}{4}=\frac{7\cdot 4+1}{4}=\frac{29}{4}$

So the equation becomes

$\frac{29}{4}+x=\frac{55}{4}$

Now we multiply by 4 each term on both sides, and we get

$29+4x=55$

Now we subtract 29 from both sides,

$4x=55-29=26$

And finally, we divide both sides by 4:

$x=\frac{26}{4}=\frac{13}{2}=6\frac{1}{2}$

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4 0

3 years ago

Read 2 more answers