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7nadin3 [17]
3 years ago
6

Which function has an inverse that is a function?

Mathematics
1 answer:
nalin [4]3 years ago
3 0
C is the answer !!!!!!!!!
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Need help understanding this problem.​
harina [27]
Basically it’s r=c/2pi meaning it’d be r=62/2(3.14) which would give you r=9.87
5 0
2 years ago
Andre bought a new bag of cat food. The next day, he opened it to his cat. The graph shows how many ounces was left in the bag o
Viktor [21]

Answer:

There were 16 ounces of Cat Food after 24 days.

Step-by-step explanation:

From the graph attached,

For an ordered pair (x, y) lying on the graph,

x-coordinate represents the number of days since bag was bought and y- coordinate represents the ounces of cat food required.

Now the value x = 24 on x-axis shows the number of days since the bag was bought.

For x = 24, ounces of cat food in the bag ( y ) = 16 ounce

Therefore, 16 ounces of Cat Food were in the bag after 24 days since it was bought.

7 0
3 years ago
Plss someone answer I need the answer ASAP
Luba_88 [7]

Answer:

7560 cubic units

Step-by-step explanation:

10×9×7×12= 7560

Sorry if Im wrong :)

6 0
2 years ago
Help! ASAP! Can somebody help me evaluate this problem
grandymaker [24]
It's a computation. It would be 8!/3!(8-3)! If my memory serves me correctly.
5 0
3 years ago
For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
3 years ago
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