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alukav5142 [94]

3 years ago

7

2,776,714 rounded to the greatest place value is?How many zeros are in the rounded number?The estimated speed of light using a p

ower of 10 is? *

1 answer:

Simora [160]3 years ago

7 0

Answer:

3,000,000. 6 Zeros. 898,752,432,640

299,792 kilometers per second is the speed of light normally

Step-by-step explanation:

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N-9 = 13<br> ------------------

Vera_Pavlovna [14]

Answer:

n-9=13

n=22

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Greg has an MP3 player called the Jumble. The Jumble randomly selects a song for the user to listen to. Greg's Jumble has 6 clas

zhannawk [14.2K]

An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or …show more content…
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side.
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day.

7 0

3 years ago

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"<span>Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find </span><span> $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
</span><span> $\bar{d} = \frac{6}{8} = 0.75$ </span>

B) Find <span> $s_{d}$
</span><span>You are asked to find the standard deviation, which is given by the formula:
</span> $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us <span> $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346</span>
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find <span> $t_{\alpha / 2} = 1.895$ </span>

Since our t-value is less than <span> $t_{\alpha / 2}$ </span> we can reject our null hypothesis!!

7 0

3 years ago

A function is shown in the table below. What equation represents this function?

Sunny_sXe [5.5K]

Answer:

y=-30+6+6 I hope it helps

have a good night

3 0

2 years ago

HELLPPPPPPPPPPPPPPPPP

forsale [732]

Answer:

y=-1/3x-8

Step-by-step explanation:

Here is the equation for slope-intercept form: y=mx+b

Ok first, let's find the y intercept, which is equal to b in slope-intercept form.

To find the y intercept, we need to look at the y axis. It is the point where the line touches it. The graph shows that the line touches the y axis at -8, so that is the y intercept, (0, -8).

Now, from that point, we need to find the slope, which is equal to m in slope-intercept form.

To find the slope, start on the point that you are on, which should be the y intercept, and count how many spaces you need to go up or down, and then left or right until you get to any other point on the line. These are called the rise (change in y) and run (change in x) respectively. The slope is equal to the rise over the run, or rise/run.

In this case, we can choose any point on the line that is shown on the graph that isn't the y intercept. I'll chose the point on the right nearest to the y intercept. From the point we are on, which is (-8,0), we will need to move one space down and three to the right.

One space down on the y axis is -1, and three spaces to the right on the x axis is +3, so our slope will be -1/+3, which is -1/3.

Let's go back to the slope-intercept form. y=mx+b. Now we can plug our information in.

We know the y intercept is -8, which is b,

and we know the slope is -1/3, which is m.

So substituting for b and m, we get y=-1/3x-8.

6 0

2 years ago