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Westkost [7]
2 years ago
7

Solve the equation: q –10 = -10

Mathematics
2 answers:
sergij07 [2.7K]2 years ago
6 0

Answer:

q=0

Step-by-step explanation:

liberstina [14]2 years ago
6 0
<h3>Answer: q = 0</h3>

-----------------------------

q - 10 = - 10

q = 0

<3

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Use 1 stone  = 14 pounds  to convert 13  stones  into  pounds​
irinina [24]

Answer:

Step-by-step explanation:

I stone = 14 pounds

13 stones =14*13

13 stones = 182 pounds

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3 years ago
Yes or no, are these functions
Hoochie [10]
Yes it is a function
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The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard
arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ 1^s^t statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

\frac{X-\mu}{\sigma} = Z

In this case we have:  \mu=5\ ft\sigma=0.4\ ft

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒2^n^d statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft  

Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒3^r^d statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒4^t^h statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3

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6 0
3 years ago
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Answer:

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Step-by-step explanation:

ln ( 2e /x)

We know that ln ( a/b) = ln ( a) - ln (b)

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ln ( 2) + ln e  - ln x

We know that the ln e = 1

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Changing the order

1 + ln 2 - ln x

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A new drug is being tested on mice. One dozen mice are given the new drug and tested, while another dozen mice are not given any
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i would have to say Census

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