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nataly862011 [7]
3 years ago
5

The angle measures 36°, 62°, 118°, and 144° are written on slips of paper. You choose two slips of paper at random.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0

1/4 would be the answer. Let me explain why first. You have in total 4 numbers with different out comes when added together. So your equation will start out as 4² = 16 out of the 16 different factors you have 4 sets that equal 180°. Your new fraction would be 4/16 which can be divided by 4 to equal 1/4. Hopes that helps!

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Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g
Galina-37 [17]
<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
</span>
7 0
3 years ago
Figure 1 is dilated to get Figure 2.
Anastasy [175]
Answer: 2.25

Divide the corresponding values. You'll divide figure 2's length over figure 1's corresponding length. So 18/8 = 2.25

This means each side of figure 2 is 2.25 times larger than the corresponding side for figure 1
3 0
2 years ago
Read 2 more answers
The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?
11111nata11111 [884]

we have

A(-2, 2),B(6, 2),C(0, 8)

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

P=AB+BC+AC

and

the area of the triangle is equal to

A=\frac{1}{2}*base *heigth

in this problem

base=AB\\heigth=DC

we know that

The distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Step 1

<u>Find the distance AB</u>

A(-2, 2),B(6, 2)

Substitute the values in the formula

d=\sqrt{(2-2)^{2}+(6+2)^{2}}

d=\sqrt{(0)^{2}+(8)^{2}}

dAB=8\ units

Step 2

<u>Find the distance BC</u>

B(6, 2),C(0, 8)

Substitute the values in the formula

d=\sqrt{(8-2)^{2}+(0-6)^{2}}

d=\sqrt{(6)^{2}+(-6)^{2}}

dBC=6\sqrt{2}\ units

Step 3

<u>Find the distance AC</u>

A(-2, 2),C(0, 8)

Substitute the values in the formula

d=\sqrt{(8-2)^{2}+(0+2)^{2}}

d=\sqrt{(6)^{2}+(2)^{2}}

dAC=2\sqrt{10}\ units

Step 4

<u>Find the distance DC</u>

D(0, 2),C(0, 8)

Substitute the values in the formula

d=\sqrt{(8-2)^{2}+(0-0)^{2}}

d=\sqrt{(6)^{2}+(0)^{2}}

dDC=6\ units

Step 5

<u>Find the perimeter of the triangle</u>

P=AB+BC+AC

substitute the values

P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units

P=22.81\ units

therefore

The perimeter of the triangle is equal to 22.81\ units

Step 6

<u>Find the area of the triangle</u>

A=\frac{1}{2}*base *heigth

in this problem

base=AB=8\ units\\heigth=DC=6\ units

substitute the values

A=\frac{1}{2}*8*6

A=24\ units^{2}

therefore

the area of the triangle is 24\ units^{2}

4 0
3 years ago
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Can someone help me on this math problem ?
faltersainse [42]

Answer:

4/3

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Given two points, we can find the slope by using

m = (y2-y1)/(x2-x1)

    = (20 - -16)/(7 - -20)

    = (20+16)/(7+20)

    = 36/27

   =4/3

8 0
3 years ago
40 boys and 16 girl possible ratios ​
Inessa05 [86]

Answer:

40:16, 16:40, 40/16, 16/40

6 0
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