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3 years ago

Suppose the diameter of a circle is 16, What is its radius?

Mathematics

2 answers:

BartSMP [9]3 years ago

8 0

The radius is 8. Half of a diameter is the radius and the radius multiplied by 2 is the diameter.

Advocard [28]3 years ago

3 0

It would be 8 because it is half the diameter.

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Which of the following is ordered from least to greatest?

zubka84 [21]

The fourth one should be the correct answer

5 0

3 years ago

Read 2 more answers

How do I factor x^4-5x^2+6?

Vilka [71]

Answer:

$=(x^2-3)(x^2-2)$

Step-by-step explanation:

So we have the expression:

$x^4-5x^2+6$

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

$=u^2-5u+6$

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

$=u^2-2u-3u+6$

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

$=u(u-2)-3(u-2)$

Grouping:

$=(u-3)(u-2)$

Now, substitute back the x² for u:

$=(x^2-3)(x^2-2)$

And this is the simplest form.

And we're done!

3 0

3 years ago

Find the volume of a cylinder that has a radius of 11 m and a height of 9 m.

hjlf

Answer:

The volume would be 3,421.19m

7 0

2 years ago

Find the value of x and y in the following figure where ABCD is a parallelogram<br><br>

asambeis [7]

Answer:

x = 3

y = 2

Step-by-step explanation:

Diagonals of a parallelogram bisect each other into two equal segments. Therefore:

3x - 1 = 2(x + 1)

Solve for x

3x - 1 = 2x + 2

Collect like terms

3x - 2x = 1 + 2

x = 3

Also:

5y + 1 = 6y - 1

Collect like terms

5y - 6y = -1 - 1

-y = -2

Divide both sides by -1

y = -2/-1

y = 2

5 0

3 years ago

What is the square root of 5x^2 = 300

vesna_86 [32]

So, values of x are: $x=2\sqrt{15},\,\,x=-2\sqrt{15}$

Step-by-step explanation:

We need to find the square root of 5x^2 = 300

Writing in mathematical form:

$5x^2=300$

Divide both sides by 5

$\frac{5x^2}{5}=\frac{300}{5}$

$x^2=60$

Taking square root on both sides

$\sqrt{x^2}=\sqrt{60}$

$x=\pm (\sqrt{2\times 2\times 3\times 5})$

$x=\pm (\sqrt{2^2 \times 3\times 5})$

$x=\pm (2\sqrt{3\times 5})$

$x=\pm (2\sqrt{15})$

$x=2\sqrt{15},\,\,x=-2\sqrt{15}$

So, values of x are: $x=2\sqrt{15},\,\,x=-2\sqrt{15}$

Keywords: Square root

Learn more about square root at:

#learnwithBrainly

7 0

3 years ago