Ask question

Ask question

All categories

3 years ago

10

A square stepping stone has a side length of 10 1/4 inches.

2 answers:

Svetach [21]3 years ago

8 0

Area=2.5

Step-by-step explanation:

area

$area = length \times width$

$area = 10 \times \frac{1}{4}$

rewona [7]3 years ago

6 0

Area of square = 4*length of one side
If one side = 10 1/4 inches = 10.25 inch
Then
Area = 4* 10.25 = 41 inches^2

You might be interested in

Which of the following is an example of independent events?

Zolol [24]

The correct answer is Choice B because each of these events are separate items. Each of the others choices will have a part of the additional events that are affected by the first event. When the first event happens in each of these options, the second event's probability is affected by the first outcome. The number of total outcomes changes because of the first event in all choices, except for choice B.

3 0

3 years ago

Plzzzzzzzzzzzzzzz help what is 6+x÷3=13

saveliy_v [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Juan will spend at most on gifts. So far, he has spent . What are the possible additional amounts he will spend?

Andru [333]

Can you send a photo of it? I can't understand

7 0

3 years ago

HELP HELP HELP I NEED HELP ASAP IM BEHIND IN MATH

geniusboy [140]

Answer:

linear i think

Step-by-step explanation:

please mark Brainliest

4 0

3 years ago

Read 2 more answers

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

$P (E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

${20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

${3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$=\frac{3}{190}\\$

$=0.01579\\\approx0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0

3 years ago