Ask question

Ask question

All categories

4 years ago

14

for an experiment you need to dissolve 0.05 moles of NaCl in one liter of water. how much NaCl must you weigh out?

2 answers:

olga nikolaevna [1]4 years ago

4 0

for an experiment you need to dissolve 0.05 moles of NaCl in one liter of water. how much NaCl must you weigh out?

2.9 i just took the test

Stels [109]4 years ago

3 0

Answer:

you must weight out 8.2 g

You might be interested in

Is 7,83 rational or irrational

RUDIKE [14]

Answer:

rational

Step-by-step explanation:

(was the comma supposed to be there?)

8 0

3 years ago

Evaluate the following expression for w=4. w^-3 =

slega [8]

W^-3
(4)^-3 = 1/(4)^3
1/64.

The solution is 1/64.

6 0

3 years ago

A 99-inch board is cut into two pieces. One piece is two times the length of the other. Find the length of the shorter piece.

Ann [662]

Answer:

33 inches

Step-by-step explanation:

x=length of board

x+2x=99

3x=99

x=33

4 0

3 years ago

Read 2 more answers

Write the arithmetic sequence that has four arithmetic means between -20 and 20.

bearhunter [10]

Let the terms be

a , a+d, a+2d, a+3d, a+4d a + 5d

so a = -20
and a + 5d = 20

-20 + 5d = 20
5d = 40 so
d = 8

-20,-12,-4,4,12,20 is the required sequence.

8 0

4 years ago

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim

geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

$\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i$

$[a, b] = [-8, 6]$

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x$

Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$

Therefore, the answer to the integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

5 0

3 years ago