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devlian [24]
4 years ago
11

Five students and two teachers attend a conference at Statistics Canada. They pose for a picture. In how many ways can they line

up, side by side, for a picture? In how many ways can they line up if they must have the teachers on both sides of the picture? What is the probability that the two teachers occupy two of the three middle slots?
Mathematics
1 answer:
oksian1 [2.3K]4 years ago
4 0

Answer:

480 ways

240 ways

Probability = 1/7

Step-by-step explanation:

Given:

Number of student = 5

Number of teacher = 2

Computation:

1. Number of ways can they line up, side by side, for a picture.

5! × 2! × 2

480 ways

2. Number of ways can they line up if they must have the teachers on both sides of the picture.

5! × 2!

240 ways

3. Probability that the two teachers occupy two of the three middle slots.

³C₂ × 5! × 2!

720 ways

Total number = 7! = 5,040 ways

Probability = 720 / 5,040

Probability = 1/7

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3 years ago
Angles α and β are angles in standard position such that: α terminates in Quadrant II and sinα = 3/5, β terminates in Quadrant I
777dan777 [17]

We are given

Angles α and β are angles in standard position

and

α terminates in Quadrant II

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sin(\alpha)=\frac{3}{5}

we can use triangle and find cos(α)

we get

cos(\alpha)=-\frac{4}{5}

and we have

cos(\beta)=\frac{4}{5}

we can draw triangle

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now, we can use formula

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now, we can plug values

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now, we can simplify it

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cos(\alpha+\beta)=-\frac{(16+9)}{25}

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3 years ago
The figure shows secants LH and and tangent J intersecting at point L. AHIL is a right triangle. Find m/HLJ, which is
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The values of x and y from the given diagram are 47 ad 86 degrees respectively

<h3>Circle theorem</h3>

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Learn more on circle theorem here: brainly.com/question/26594685

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