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3 years ago

Anyone know how to do this kind of algebra?

1 answer:

3 0

$\Delta_A=5^2-4\cdot3\cdot1=25-12=13\\
\Delta_B=(-5)^2-4\cdot3\cdot1=25-12=13\\$

Both discriminants are equal.

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The ratio of green marbles to yellow marbles in Toby’s bag is equal to 2:3. What percent of the marbles in the bag are green mar

Andrews [41]

40% is the answer. you create a ratio and percent table is a way of solving it. Hope this helps!

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3 years ago

Read 2 more answers

The picture is my problem.

Sidana [21]

Answer:

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2 years ago

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GalinKa [24]

Answer:

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Step-by-step explanation:

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2 years ago

The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive

murzikaleks [220]

Answer:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

$X \sim Unif (a=0, b =12)$

And we want to find the following probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0

3 years ago

Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 3/2

Soloha48 [4]

ANSWER

See attachment

EXPLANATION

The given inequality is

$|x| \: > \: \frac{3}{2}$

This implies that,

$x\: > \: \frac{3}{2} \: or \: - x\: > \: \frac{3}{2}$

Multiply both sides of the second inequality by -1 and reverse the inequality sign.

$x\: > \: \frac{3}{2} \: or \: x\: < \: - \frac{3}{2}$

The graphical solution to this inequality is shown in the attachment.

7 0

2 years ago