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mel-nik [20]
3 years ago
13

Anyone know how to do this kind of algebra? 

Mathematics
1 answer:
katovenus [111]3 years ago
3 0
<u>\Delta_A=5^2-4\cdot3\cdot1=25-12=13\\&#10;\Delta_B=(-5)^2-4\cdot3\cdot1=25-12=13\\

</u>Both discriminants are equal.<u>
</u>
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Can someone help me,it would be appreciated.Thanks!!! :D
Ierofanga [76]

The number of pieces of 1/3 foot tall to make a 6 feet skyscraper is 18 pieces.

The model of a skyscraper comes in pieces and each piece is 1/3 feet tall.

After all the pieces are put together the skyscraper is 6 feet tall.

We have to calculate how many pieces were put together to make the 6 feet skyscraper.

Let X be the number of pieces put together to make a 6 feet skyscraper.

Now,

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Since all the pieces together make 6 feet tall, we can write the number of pieces needed to make 6 feet tall as:

X x (1/3) = 6

X = 6 x 3 = 18

Thus, we need 18 pieces of 1/3 foot tall to make a 6 feet skyscraper.

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