3 years ago

Solve for -6= b/18

Mathematics

1 answer:

irga5000 [103]3 years ago

7 0

Answer:

b= -108

Step-by-step explanation:

we have:

-6= b/18

b= -6*18

b= -108

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Points B and B' have symmetry with respect to P. Find the coordinates of P when B is (2, 8) and B' is (2, 2). A. (2, 5) B. (0, 5

Alecsey [184]

Answer:

A. (2, 5)

Step-by-step explanation:

If B and B' have symmetry, then P is a midpoint between those points. We can determinate the location of point P by using the midpoint equation, whose vectorial form is:

$P(x,y) = \frac{1}{2}\cdot B(x,y)+\frac{1}{2}\cdot B'(x,y)$ (Eq. 1)

If we know that $B(x,y) = (2,8)$ and $B'(x,y) = (2,2)$ , then the location of P is:

$P(x,y) = \frac{1}{2}\cdot (2,8)+\frac{1}{2}\cdot (2,2)$

$P(x,y) = (1, 4)+(1,1)$

$P(x,y) = (2, 5)$

Which corresponds to option A.

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3 years ago

For working 13 hours you earn $58.50 and $121.50 for 27 hours. What is your rate of pay in dollars per hour?

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Y2-y1/x2-x1
121.5-58.5/27-13
63/14
$4.5 an hour.

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3 years ago

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Step-by-step explanation:

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3 years ago

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Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).

sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

$(p^4-q^4)(p^4+q^4)$ $\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}$

Therefore, the expression can be simplified as;

$p^8-q^8$

Alternatively, using the theorem of difference of two squares, which is

$a^2-b^2=(a-b)(a+b)$

Hence,

$p^8-q^8=(p^4)^2-(q^4)^2$

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1 year ago

Which of the following can be used to represent a loss of $320. -320, 0, 1 over 320, +320

Radda [10]

-320. The negative sign represents loss. In all of the other cases, values are either being added or not changed at all.

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3 years ago