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motikmotik
3 years ago
13

What are the solutions to the equation y² + 16 = 212?

Mathematics
2 answers:
Levart [38]3 years ago
6 0
Y² + 16 = 212 
<span>y</span>² <span>= 196 </span>
<span>y = -14 and 14</span>
anyanavicka [17]3 years ago
4 0
y^2 + 16 = 212\\&#10;y^2=196\\&#10;y=-14 \vee y=14
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Rename the number to 120,000 ten thousand
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Need help on the last problem please.
pshichka [43]

Answer:

6 of x and 5 of y

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x = number of closets of the first type

y = number of closets of the second type

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6 0
3 years ago
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
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