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erastovalidia [21]
3 years ago
13

The graph shows the relationship between time and distance is Pam rides her bike. During which time period was the rate of chang

e the greatest?
Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
4 0
Where is the graph ?
deff fn [24]3 years ago
4 0
Are there any options or anything

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How to find the missing numbers in two digit division
abruzzese [7]

Answer:

Divide the first number of the dividend (or the two first numbers if the previous step took another digit) by the first digit of the divisor. Write the result of this division in the space of the quotient. Multiply the digit of the quotient by the divisor, write the result beneath the dividend and subtract it.Jun

Step-by-step explanation:

pls brainlist

3 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
Can some one PLEASE give me brainliest
KIM [24]

Answer:

You gotta deserve it

Step-by-step explanation:

8 0
4 years ago
Solve 2-18x-6=-7x+3+10x
Temka [501]

Answer:

x= -1/3

Step-by-step explanation:

First, we can combine like terms on each side:

-4-18x=3x+3

Then, we move all of the variables onto one side and the constant onto the other:

-18x-3x=3+4

-21x=7

x=-7/21

x= -1/3

Hope this helps!

7 0
4 years ago
Read 2 more answers
What is the slope of the line?
rodikova [14]

Answer:

Step-by-step explanation:

If you look careful,the line is passing throw the middle of the square which that means 0,5=>1/2

3 0
3 years ago
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