372
The number 3 is in the hundreds place.
Look to the number immediately to the right.
We know that 7 is bigger than 3.
So, we add 1 to 3 and the rest become 0.
Answer: 400
Answer:
40
Step-by-step explanation:
Based on the Proportional Transversal Theorem, the three parallel lines hat intersects the two transversals, divides the transversal lines proportionally.
Therefore, we would have the following ratio:
28/35 = ?/50
Cross multiply
35*? = 50*28
35*? = 1,400
Divide both sides by 35
? = 1400/35
? = 40
D, because the will not intersect i believe
Answer:
There is a 34.3% probability that he makes all of the shots.
Step-by-step explanation:
For each foul shot that he takes during the game, there are only two possible outcomes. Either he makes it, or he misses. This means that we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
In this problem we have that:
![n = 3, p = 0.7](https://tex.z-dn.net/?f=n%20%3D%203%2C%20p%20%3D%200.7)
What is the probability that he makes all of the shots?
This is P(X = 3).
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 3) = C_{3,3}.(0.7)^{3}.(0.3)^{0} = 0.343](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%20C_%7B3%2C3%7D.%280.7%29%5E%7B3%7D.%280.3%29%5E%7B0%7D%20%3D%200.343)
There is a 34.3% probability that he makes all of the shots.
Well,
We can read 9.33 as 9 and 33 hundredths.
In fraction form that would be:
![9 \frac{33}{100}](https://tex.z-dn.net/?f=9%20%20%5Cfrac%7B33%7D%7B100%7D%20)
That is already simplest form.
If you meant
![9. \overline{3}](https://tex.z-dn.net/?f=9.%20%5Coverline%7B3%7D)
, then it would be: