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Anarel [89]
3 years ago
6

A computer technician charges a flat base fee plus an hourly rate for all repairs. Last year, she used the formula to determine

the cost in dollars, y, of a repair that required x hours of work. If she doubles her base fee this year, what equation should she use to determine the new cost of an x-hour repair?
Mathematics
2 answers:
Len [333]3 years ago
5 0

Answer: 2x + base fee =y

Step-by-step explanation:

Well the original equation before the doubling would be the base fee + x = y so all you have to do is double that. :)

olya-2409 [2.1K]3 years ago
4 0

Answer:

2x + base fee =y

Step-by-step explanation:

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Please help ASAP<br><br> If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x)<br> b.) (gof) (-2)
Rudik [331]
\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}


\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}

______


\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}

______


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559


\large\textsf{I hope this helps. :-)}


Tags: <em>composite function composition evaluate algebra</em>

7 0
3 years ago
5. Let f be a continuous and differentiable function for all real numbers. The only critical points for f are located
ollegr [7]
Ok so the answer is super simple, its A
6 0
3 years ago
Here are two rectangles.
Sophie [7]

Answer:

AB=9.5\ cm

Step-by-step explanation:

step 1

Find the length side PQ

we know that

The area of rectangle PQRS is given by

A=(PQ)(QR)

A=66\ cm^2

so

66=(PQ)(QR)

substitute the value of QR

66=(PQ)(12)

solve for PQ

PQ=66/12\\PQ=5.5\ cm

step 2

Find the length side AB

we know that

The perimeter of rectangle ABCD is given by

P=2(AB+BC)

we have

P=30\ cm\\BC=PQ=5.5\ cm

substitute

30=2(AB+5.5)

solve for AB

15=AB+5.5\\AB=15-5.5\\AB=9.5\ cm

6 0
3 years ago
If A is a square matrix of order 2, then det(-3A) is *
Vsevolod [243]

Answer:

c. 9 det A

Step-by-step explanation:

Given the following data;

Since A is a square matrix of order 2, we know that n = 2

K = 3

For any scalar k;

∣kA∣ = k^{n} ∣A∣

<em>Substituting into the equation;</em>

∣-3A∣ = -3²∣A∣

Simplifying, we have;

∣-3A∣ = 9∣A∣

= 9 detA

<em>Therefore, det (-3A) = 9 detA</em>

6 0
3 years ago
Read 2 more answers
What’s the domain of this graph??
charle [14.2K]

the domain of the graph is where on the x axis there is a graph.

here the domain, x, is less than or equal to 6, isnce it goes down on the negative side

the arrow means the line goes on forever, so

x<=6

(x is less than or equal to 6)

6 0
2 years ago
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