Answer:
The angles are 79.45, 59.02 and 41.53 degrees to the nearest hundredth.
Step-by-step explanation:
We have a triangle with sides of length 8.6, 5.8 and 7.5 feet.
Using the Cosine Rule to find the measure of the angle opposite the side of length 8.6 feet:
cos X = (8.6^2 - 5.8^2 - 7.5^2) / ( -2*5.8*7.5)
= 0.18310
X = 79.45 degrees.
We can now find another angle using the sine rule:
8.6 / sin 79.45 = 7.5/ sin Y
sin Y = (7.5 * sin 79.45) / 8.6
Y = 59.02 degrees
So the third angle = 180 - 79.45 - 59.02
= 41.53 degrees.
Make the same denominator (12) and then make them both non mixed numbers 93/12 and 54.6666.../12
so 147.666.../12
12.305/12
The answer is A!
-4.82, -4(2/3) = - 4.667, sqrt 15 is 3.873, 4.15, 465% is 4.65, and 1.5pi =4.65
Hope this helps!
<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
Answer:
Pages 100 and 101
Step-by-step explanation:
Round 201 to 200 (to make it easier).
Divide 200 by 2, because it is 2 pages.
You are left with 100.
100 is one of the pages, but because you rounded down 1 number, the other number must be 101, because the pages are back to back.
I hope this made sense, this is just how I figured it out. :)
