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2 years ago

14

Which shows the list above in order from LEAST to GREATEST I’ll mark brainlist : )

1 answer:

irina1246 [14]2 years ago

7 0

The answer is A!

-4.82, -4(2/3) = - 4.667, sqrt 15 is 3.873, 4.15, 465% is 4.65, and 1.5pi =4.65
Hope this helps!

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Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

When calculating the circumference of a circle, sometimes the radius is given instead of the diameter. What is the relationship

alex41 [277]

The diameter is double the size of the radius

3 0

2 years ago

Read 2 more answers

Please help me and Katie don’t delete it

artcher [175]

Answer:

A.

I say this is the answer because if she has gotten into a habait of buying and breaking glasses,shes just very careless

8 0

3 years ago

the sum of three numbers is 11. if you triple the second number and add the third number, the result will be equal to the first

leonid [27]

<span>1st number = 11, 2nd number = 5.5, 3rd number = -5.5</span>

3 0

3 years ago

Write the equation. Nell sold 125 packages of cookies at the bake sale. Each package was tied with 2 ribbons. How many ribbons w

Bingel [31]

Answer:

Equation: 125 x 2 = x

250 ribbons

Step-by-step explanation:

We have to find the total number of ribbons used. Since Nell sold 125 packages of cookies and each package has 2 ribbons, we can make the equation 125 x 2 = x. Let x = the number of ribbons used in total. We multiply them to get 250. Therefore, 250 ribbons were used.

I hope this helped and please mark me as brainliest!

5 0

2 years ago