The soccer team collector $800 at a carwash fundraiser they charge five dollars for small vehicles and $10 for large vehicles th
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Part A: The y-intercept is 5. If you look to the data, when x=0, y=5. This means that the turtle started off 5 miles away from its nest. (at 0 hours, the distance away from his nest was 5 miles)
Part B:Answer=22. Remember, if you take any two distinct points on a line, the slope of the line will be equal to the average rate of change. In short, we're just looking for the slope between the ordered pairs (1,27) and (4,93). The formula for slope is:
The average rate of change between x=1 and x=4 is 22. The average rate of changed describes the rate at which miles is changing with respect the the change in hour.
Part C: Answer=10hours. Since by now we know both the slope and the y-intercept, lets write the equation in slope intercept form and then solve for 225 miles.
y=mx+b
y=22x+5
225=22x+5
subtract 5 from both sides
220=22x
divide both sides by 22
10=x
It would take 10 hours for the turtle to travel 225miles from it's nest.
Part B:Answer=22. Remember, if you take any two distinct points on a line, the slope of the line will be equal to the average rate of change. In short, we're just looking for the slope between the ordered pairs (1,27) and (4,93). The formula for slope is:
The average rate of change between x=1 and x=4 is 22. The average rate of changed describes the rate at which miles is changing with respect the the change in hour.
Part C: Answer=10hours. Since by now we know both the slope and the y-intercept, lets write the equation in slope intercept form and then solve for 225 miles.
y=mx+b
y=22x+5
225=22x+5
subtract 5 from both sides
220=22x
divide both sides by 22
10=x
It would take 10 hours for the turtle to travel 225miles from it's nest.
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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