3 years ago

How many legs were there in the presents over the twelve days in the twelve days of Christmas???

1 answer:

mina [271]3 years ago

4 0

202

(12x2) +22+20+18+72+14+12+0+8+6+4+2= 202

You might be interested in

MAXImum [283]

I would say 3. 21/7=3. 3 boxes. 7 hard in each.

8 0

3 years ago

Sav [38]

Answer:

n>-13

Step-by-step explanation:

so you subtract 4 from -9 then since your not multiplying or divinding by a negative you don't flip the sign

3 0

2 years ago

Debora [2.8K]

Answer:

Step-by-step explanation:

8 0

2 years ago

Helga [31]

Answer:

$m=\frac{-2}{5}$

Step-by-step explanation:

Use the formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Plug in the numbers (coordinates) given, like so:

$m=\frac{3-7}{6+4}$

$m=\frac{-4}{10}$

Simplify:

$m=\frac{-2}{5}$

7 0

3 years ago

Mila [183]

450/2,970*100
450*10/297=15.2

7 0

3 years ago